The time elapsed when the ball placed above the concave mirror and the image formed would be at the same location is 0.55 s.
<h3>Image distance</h3>
The position of the image formed is determined using the followimg mirror formula;

where;
- f is the focal length of the mirror
- v is the image distance
- u is the object distance
f = R/2
f = 1.5/2
f = 0.75 m
When the ball and its image is in the same position, u = v
The position of the ball is calculated as;

<h3>Time of motion of the ball</h3>
The time taken for the ball to travel the caluclated distance is determined as;
h = ut + ¹/₂gt²
1.5 = 0 + ¹/₂(9.8)t²
1.5 = 4.9t²
t² = 1.5/4.9
t² = 0.306
t = 0.55 s
Thus, the time elapsed when the ball and its image are at the same location is 0.55 s.
Learn more about concave mirror here: brainly.com/question/7512320
A 3.1 L sample of hydrogen <u>d. contains the same number of molecules</u>
as 3.1 L of carbon dioxide at the same temperature and pressure.
This is the fundamental principle of <em>Avogadro’s hypothesis</em>: equal volume of gases at the same temperature and pressure contain the same number of molecules.
The sample of carbon dioxide has a <em>greater mass</em>, a <em>greater number of atoms</em>, and a <em>greater density</em>, than the sample of hydrogen.
<span>I believe your answer is stage Meiosis.
Hope this helps!</span>
Answer:
it would be 5 and 3??? right
Explanation:
hope this helps