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suter [353]
2 years ago
14

What product is released into Earth's atmosphere through the combustion of fossil fuels?

Chemistry
1 answer:
mezya [45]2 years ago
7 0

Answer:

Carbon Monoxide

Explanation:

Fossil fuels are hydrocarbons which only contain hydrogen and carbon.

When it is burnt in air, it reacts according to this general equation:

2(CH) + 3O2 >> H2O + CO + CO2

  • Carbondioxide
  • Carbon Monoxide
  • Water
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How many miligrams are in 75 nanogram?​
Naddik [55]

Answer:

7.5e-5 that's the answer

6 0
3 years ago
Compare and contrast the bonds in these two compounds: MgCl2 and C2H6. Include similarities and differences. Be sure to discuss
devlian [24]
Both of the compounds contain primary bonding; however, the bonding is of different types. Magnesium chloride (MgCl₂) contains ionic bonds, which are stronger and involve the complete transfer of electrons. Meanwhile, ethane (C₂H₆) also bonds by electron transfer but the electrons are not completely transferred from one atom to another. Instead, they are shared, forming what is known as a covalent bond. 
8 0
3 years ago
Which compound does not form a precipitate when reacted with sodium hydroxide?
Alla [95]

Answer:

NaNO₃

Explanation:

A precipitate is a compound or a salt formed from a precipitation reaction and does not dissolve in water and therefore will exist in solid state.

From the choices given precipitation reaction will occur between;

  • Fe(NO₃)₃(aq) + 3NaOH(aq) → Fe(OH)₃(s) + 3NaNO₃(aq)
  • Cu(NO₃)₂(aq) + 2NaOH(aq) → Cu(OH)₂(s) + 2NaNO₃(aq)
  • FeSO₄(aq) + 2NaOH(aq) → Fe(OH)₂(s) + Na₂SO₄(aq)

Fe(OH)₃, Cu(OH)₂, and Fe(OH)₂ are precipitates.

From the rules of solubility, hydroxides are insoluble except Ca(OH)₂ which is slightly soluble and hydroxides of ammonium and alkali metals.

5 0
4 years ago
How many electrons will strontium lose to satisfy the octet rule?
Law Incorporation [45]

Answer:

Two Electrons.

Explanation:

Strontium is the atom with atomic number 38, and electron configuration is [Kr] 5S^2 which mean just two electrons more than Krypton which one of the Noble gases.

8 0
3 years ago
C. If 62.9 g of lead (II) chloride is produced, how many grams of lead (II) nitrate were
melomori [17]

Answer:

Mass = 76.176 g

Explanation:

Given data:

Mass of lead(II) chloride produced = 62.9 g

Mass of lead(II) nitrate used = ?

Solution:

Chemical equation:

Pb(NO₃)₂  +  2HCl     →     PbCl₂ + 2HNO₃

Number of moles of lead(II) chloride:

Number of moles = mass/molar mass

Number  of moles = 62.9 g/ 278.1 g/mol

Number of moles = 0.23 mol

Now we will compare the moles of lead(II) chloride with Pb(NO₃)₂ from balance chemical equation:

                            PbCl₂        :          Pb(NO₃)₂

                               1             :             1

                             0.23         :            0.23

Mass of Pb(NO₃)₂:

Mass = number of moles ×  molar mass

Mass = 0.23 mol × 331.2 g/mol

Mass = 76.176 g

8 0
4 years ago
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