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3 years ago

Will give brainliest

Chemistry

1 answer:

oksian1 [2.3K]3 years ago

3 0

CONJUGATE ACID

the acid's conjugate base because it can theoretically reform the acid by aaccepting a proton.

I hope this is correct >.<

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How do you write 3.40 x 10 to the eighth power in standard form?

solong [7]

Answer:

272

Explanation:

hope it helps i double checked the math :D

7 0

3 years ago

PLEASE ANSWER FAST!!

nydimaria [60]

The summers in Michigan and Florida are similar because the plants in both regions end their periods of dormancy, trees start to grow buds, and plants begin to flower.

<h3>What are the effects of summer in plants in Michigan and Florida?</h3>

Summer is a period of increased sunshine and usually results in increased in plant growth and development.

Florida experienced an increased sunshine in summer periods.

Similarly, in Michigan, plants grow abundantly in summer time.

Therefore, the summers in Michigan and Florida are similar because the plants in both regions end their periods of dormancy, trees start to grow buds, and plants begin to flower.

Learn more about summer in Michigan and Florida at: brainly.com/question/19214624

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5 0

2 years ago

For the following reaction, 4.31 grams of iron are mixed with excess oxygen gas . The reaction yields 5.17 grams of iron(II) oxi

natka813 [3]

Answer: The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For Iron:

Given mass of iron = 4.31 g

Molar mass of iron = 53.85 g/mol

Putting values in above equation, we get:

$\text{Moles of iron}=\frac{4.31g}{53.85g/mol}=0.0771mol$

For the given chemical reaction:

$2Fe(s)+O_2(g)\rightarrow 2FeO(s)$

By Stoichiometry of the reaction:

2 moles of iron produces 2 moles of iron (ii) oxide.

So, 0.0771 moles of iron will produce = $\frac{2}{2}\times 0.0771=0.0771mol$ of iron (ii) oxide

Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:

Moles of of iron (II) oxide = 0.0771 moles

Molar mass of iron (II) oxide = 71.844 g/mol

Putting values in equation 1, we get:

$0.0771mol=\frac{\text{Theoretical yield of iron(ii) oxide}}{71.844g/mol}=5.53g$

To calculate the percentage yield of iron (ii) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of iron (ii) oxide = 5.17 g

Theoretical yield of iron (ii) oxide = 5.53 g

Putting values in above equation, we get:

$\%\text{ yield of iron (ii) oxide}=\frac{5.17g}{5.53g}\times 100\\\\\% \text{yield of iron (ii) oxide}=93.49\%$

Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

7 0

3 years ago

Pyridine (c5h5n) is a particularly foul-smelling substance used in manufacturing pesticides and plastic resins. calculate the ph

zubka84 [21]

Answer is: ph value of pyridine solution is 9.1.

Chemical reaction: C₅H₅N + H₂O → C₅H₅NH⁺ + OH⁻.
c(pyridine - C₅H₅N) = 0.115M.
Kb(C₅H₅N) = 1.4·10⁻⁹.
[C₅H₅NH⁺] = [OH⁻] = x; equilibrium concentration.
[C₅H₅N] = 0.115 M - x.

Kb = [C₅H₅NH⁺] · [OH⁻] / [C₅H₅N].

1.4·10⁻⁹ = x² / (0.115 M -x)

Solve quadratic equation: x = [OH⁻] = 0.0000127 M.
pOH = -log(0.0000127 M) = 4.9

pH = 14 - 4.9 = 9.1.

7 0

3 years ago

A chemical combination of two or more atoms is a(n) .

irinina [24]

Answer:

Molecule

Explanation:

Its simple definition

6 0

3 years ago

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