Question

If there are 10.0 g of sucrose and 8.0 g of oxygen, how many moles of sucrose are available for this reaction? A.) 0.029 mol B.) 0.250 mol C.) 0.351 mol D.) 3.00 mol

Answer 1

0.029 iss the answer. 

Answer 2

Answer: A.) 0.029

Explanation: To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\textMolar mass}}$

For sodium:

Mass of sucrose given = 10 g

Molar mass of sucrose $C_{12}H_{22}O_{11}$ = 342 g/mol

Putting values in above equation, we get:

$\text{Moles of sodium}=\frac{10g}{342g/mol}=0.029mol$

Thus the number of moles of sucrose available for this reaction will be 0.029.