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saveliy_v [14]
4 years ago
14

Why is the value listed for atomic mass for each element on the periodic table not a whole number?

Chemistry
1 answer:
sweet-ann [11.9K]4 years ago
8 0
A. it is an average

You might be interested in
Part A
PilotLPTM [1.2K]

Answer:

4200ml

Explanation:

Converting 3.1kg to g

3.1*1000= 3100g

Since density = mass/volume, then

volume = mass/ density

Therefore volume = 3100/0.74

= 4189.2ml

converting it to two significant figures

= 4200ml

6 0
2 years ago
What mass is Thallium (I) sulfide will be formed from 36.00g of thallium reacting with excess sulfur
sveticcg [70]

Answer:

hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

Explanation:

SORRY

3 0
3 years ago
2C(s) + 2H2(g) → C2H4(g): ΔH = +52.4 kJ/mol<br><br> Which statement about this reaction is correct?
artcher [175]
<h3><u>Answer;</u></h3>

26.2 kJ of energy are absorbed for every mole of carbon reacted

<h3><u>Explanation;</u></h3>
  • ΔH is the enthalpy change which is given by subtracting the energy of reactants from the energy of products.
  • That is; ΔH = energy of products - energy of reactants
  • <u>In this case, it means that C2H4 has more energy than the the reactants. 52.4 J of energy to be precise, this energy is absorbed during the reaction.</u>
  • <u>However, Two moles of Carbon  require that much energy, thus one mole will require only 26.2 to react. </u>
6 0
3 years ago
A solution was prepared by dissolving 2.2 g of an unknown solute in 16.7 g of CCl4. A thermal analysis was performed for this so
laila [671]

Answer:

Molar mass of unknown solute is 679 g/mol

Explanation:

Let us assume that the solute is a non-electrolyte.

For a solution with non-electrolyte solute remains dissolved in it -

Depression in freezing point of solution, \Delta T_{f}=K_{f}.m

where, m is molality of solute in solution and K_{f} is cryogenoscopic constant of solvent.

Here \Delta T_{f}=(-22.9^{0}\textrm{C})-(-28.7^{0}\textrm{C})=5.8^{0}\textrm{C}

If molar mass of unknown solute is M g/mol then-

                 m=\frac{\frac{2.2}{M}}{0.0167}mol/kg

So, 5.8^{0}\textrm{C}=29.9^{0}\textrm{C}/(mol/kg)\times \frac{\frac{2.2g}{M}}{0.0167}mol/kg

so, M = 679 g/mol

4 0
3 years ago
Helpppp nowww plsss!!!
gayaneshka [121]

Answer:

The Sun will appear to rise and set more slowly.

5 0
3 years ago
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