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Lisa [10]
3 years ago
8

The reaction of 11.9 g of chcl3 with excess chlorine produced 11.2 g of ccl4, carbon tetrachloride: what is the percent yield?

Chemistry
2 answers:
iVinArrow [24]3 years ago
7 0
<span>73.0% First, lookup the atomic weights of the elements involved Atomic weight carbon = 12.0107 Atomic weight chlorine = 35.453 Atomic weight hydrogen = 1.00794 Calculate the molar masses. Molar mass CHCl3 = 12.0107 + 1.00794 + 3 * 35.453 = 119.37764 Molar mass CCl4 = 12.0107 + 4 * 35.453 = 153.8227 Calculate the number of moles we have Moles CHCl3 = 11.9 g / 119.37764 g/mol = 0.099683659 mol Moles CCl4 = 11.2 g / 153.8227 g/mol = 0.0728111 mol Since with 100% yield, each molecule of CHCl3 should produce one molecule of CCl4, divide the actual moles produced by the number of moles expected for 100% yield. So 0.0728111 / 0.099683659 = 0.730421623 = 73.0421623 % Rounding to 3 significant figures gives 73.0%</span>
Paha777 [63]3 years ago
3 0
First, we need to calculate the theoretical yield as follows:
The balanced chemical reaction is:
<span>2CHCl3 +2Cl2 ----> 2CCl4 +2HCl
</span>molar mass of CHCl3 = <span>119.378 grams
molar mass of CCl4 = </span>153.823 grams<span>
number of moles = mass / molar mass = 11.9 / 119.378 = 0.0997 moles
From the balanced equation, 2 moles of CHCl3 produce 2 moles of CCl4.
Therefore, 0.0997 moles of CHCl4 will produce 0.0997 moles of CCl4.
number of moles = mass / molar mass
mass (theoretical) = molar mass * number of moles
mass (theoretical) = </span><span>153.823 * 0.0997 = 15.336 grams

Now, we will calculate the percent yield as follows:
% yield = (actual mass / theoretical mass) * 100
% yield = (11.2 / 15.336) * 100 = 73.03%</span>
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Answer:

bcfh

Explanation:

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HClO₄ + H₂O → H₃O⁺ + ClO₄⁻

That means HClO₄ produce H₃O⁺ that decreases pH. That means the higher concentration of HClO₄ decreases pH. Thus, lower pH will be:

b) 0.2 M HClO4

The reaction of NaClO₄ is:

NaClO₄ + H₂O → OH⁻ + HClO₄ + Na⁺

The higher concentration of NaClO₄ the higher production of OH⁻ that increase pH, that means the lower concentration of NaClO₄ the lower pH, thus, the answer is:

<em>c) 0.1 M NaClO or</em>

HF reacts with water thus;

HF ⇄ H⁺ + F⁻

The equilibrium constant is:

k = [H⁺] [F⁻] / [HF] = 3,5x10⁻⁴

For HNO₂ equilibrium is:

HNO₂ ⇄ H⁺ + NO₂⁻

k = [H⁺] [NO₂⁻] / [HNO₂] = 4,5x10⁻⁴

As k value is higher for HNO₂, the concentration of H⁺ will be higher in this system doing the HNO₂ with the lower pH.

f) 0.1 M HNO2

NaOH is a strong base that produce OH⁻ that increase pH, pure water is neutral, thus, the lowe pH is:

h) pure water

I hope it helps!

7 0
3 years ago
If the volume of a gas container at 32 degrees Celsius changes from 1.55 L to 755 mL, what will the final temperature be?
QveST [7]
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choli [55]

Answer:

Here's it:

Explanation:

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Which is associated with a fission reaction? *
podryga [215]

Answer: Radioactive waste

Explanation:

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6 0
3 years ago
Effective nuclear charge, Zeff, is defined as:
Alborosie

Answer:

The effective nuclear charge for a valence electron in oxygen atom: Z_{eff} = 4.55

Explanation:

Effective nuclear charge  [Z_{eff}] is the net nuclear charge experienced by the electron in a given atom. It is always less than the actual charge of the nucleus [Z], due to shielding by electrons in the inner shells.

<em>It is equal to the difference between the actual nuclear charge or the atomic number (Z) and the shielding constant (s).  </em>

\Rightarrow Z_{eff} = Z - s

<u>For an oxygen atom</u>-

Electron configuration: (1s²) (2s² 2p⁴)

<em>The atomic number (actual nuclear charge): </em>Z = 8

The shielding constant (s) for a valence electron can be calculated by using the Slater's rules:

⇒ s = 5 × 0.35 + 2 × 0.85 = 1.75 + 1.7 = 3.45

<u><em>Therefore, the effective nuclear charge for a valence electron in oxygen atom is:</em></u>

Z_{eff} = Z - s = 8 - 3.45 = 4.55

<u>Therefore, the effective nuclear charge for a valence electron in oxygen atom:</u> Z_{eff} = 4.55

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2 years ago
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