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2 years ago

10. The statement that no two electrons in the same atom can have the

Chemistry

1 answer:

Fynjy0 [20]2 years ago

3 0

Answer:

10.the pauli exclusive principle statues that, in an atom

or molecules, no two electrons can have same four electronic quantum numbers.as an orbit can contain a maximum of only two electrons.the two electrons must have opposing spins

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1) G to H. 2) I to J. 3) J to I. 4) I to H.

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3 years ago

The temperature at which the vapor pressure of a liquid is equal to the external pressure is called the _____ point.

jeyben [28]

It is B. Boiling point

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3 years ago

How does the length of the day affect the seasonal temperature

astra-53 [7]

The longer the day, the solar radiation is absorbed and the higher the temperature is.

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3 years ago

At 25 °C, the equilibrium partial pressures for the following reaction were found to be PA = 8.00 atm, PB = 5.40 atm, PC = 6.90

Yuliya22 [10]

Answer: The standard change in Gibbs free energy for the given reaction is 4.33 kJ/mol

Explanation:

For the given chemical equation:

$A(g)+2B(g)\rightleftharpoons C(g)+D(g)$

The expression of $K_p$ for the given reaction:

$K_p=\frac{p_C\times p_D}{p_A\times (p_B)^2}$

We are given:

$p_A=8.00atm\\p_B=5.40atm\\p_C=6.90atm\\p_D=5.90atm$

Putting values in above equation, we get:

$K_p=\frac{6.90\times 5.90}{8.00\times (5.40)^2}\\\\K_p=0.174$

To calculate the standard Gibbs free energy, we use the relation:

$\Delta G^o=-RT\ln K_p$

where,

$\Delta G^o$ = standard Gibbs free energy

R = Gas constant = $8.314J/K mol$

T = temperature = $25^oC=[25+273]K=298K$

$K_p$ = equilibrium constant in terms of partial pressure = 0.174

Putting values in above equation, we get:

$\Delta G^o=-(8.314J/Kmol)\times 298K\times \ln (0.174)\\\\\Delta G^o=4332.5J/mol=4.33kJ/mol$

Hence, the standard change in Gibbs free energy for the given reaction is 4.33 kJ/mol

3 0

3 years ago

. What is the molarity of a solution that was prepared by dissolving 80.0 g of CaCl2 (molar mass = 111.1 g/mol) in enough water

garri49 [273]

Explanation:

Molarity = mol/L or g/L

Data:

Mass>80.0g

Mr of CaCl2>111.1g/mol

V>500mL

Convert mL to Litres;. mole=g/Mr

1L=1000mL. =80g/111.1g/mol

x=500mL. =0.720072007mol

x=0.5L

Molarity= mole/volume

=0.720072007mol/0.5L

=1.440144014mol/L

=1.4401mol/L

Hope this helps. Depending on the question you can also find it in g/L but mol/L is safer.

7 0

2 years ago