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AlekseyPX
3 years ago
14

What is the gravitational force between two cars (one car is 1500 kg and the other car is 1000 kg) in a parking lot that are thr

ee meters from each other?
Physics
1 answer:
Lana71 [14]3 years ago
8 0

Answer: Your answer 0.000002500737 in pounds-force!

Explanation: Hope my answer helped you! Plz, mark my answer as Brainliest and Thank you!

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At 45 degrees s latitude, the angle of the noon sun is lowest and the length of daylight is shortest on:
Marat540 [252]

Answer;

- June 21

At 45 degrees latitude, the angle of the noon sun is lowest and the length of daylight is shortest on June 21.

Explanation;

-On June 21 you will note that the Northern Hemisphere is pitched toward the Sun. This means that the Sun's vertical ray is striking the Earth at the Tropic of Cancer (23.5 degrees N).

-Days tend to get longer in the northern hemisphere from December 21 to June 21, and then grow shorter from June 21 to December 21.  The June solstice is the summer solstice in the Northern Hemisphere and the winter solstice in the Southern Hemisphere. The date varies between June 20 and June 22, depending on the year, and the local time zone.

8 0
3 years ago
A salt shaker sits 0.102 m from
Ivahew [28]

The maximum speed is 0.55 m/s

Explanation:

For an object in uniform circular motion, the force of friction between the object and the ground provides the centripetal force required to keep the body in motion. Therefore we can write:

\mu_s mg = m\frac{v^2}{r}

where the term on the left is the frictional force and the term on the right is the centripetal force, and where

\mu_s is the coefficient of static friction

m is the mass of the body

g is the gravitational acceleration

v is the speed of the body

r is the radius of the circular path

In this problem, we have:

\mu_s = 0.307

r = 0.102 m

g=9.8 m/s^2

Substituting and re-arranging, we find the maximum speed v at which the salt shaker can rotate:

v=\sqrt{\mu gr}=\sqrt{(0.307)(9.8)(0.102)}=0.55 m/s

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

6 0
3 years ago
A 4 kg block is pulled with 4.1 N of force to the right. The block experiences 1.0 N of
Evgesh-ka [11]

Answer:

CHECK THIS..

THANK YOU.

4 0
3 years ago
PLEASE HELP, evaporation,liquids,solids, and gases involved
sukhopar [10]
Yes they are involved
5 0
3 years ago
At a certain elevation, the pilot of a balloon has a mass of 120 lb and a weight of 119 lbf. What is the local acceleration of g
Strike441 [17]

Answer:

31.905 ft/s²

Explanation:

Given that

Mass of the pilot, m = 120 lb

Weight of the pilot, w = 119 lbf

Acceleration due to gravity, g = 32.05 ft/s²

Local acceleration of gravity of found by using the relation

Weight in lbf = Mass in lb * (local acceleration/32.174 lbft/s²)

119 = 120 * a/32. 174

119 * 32.174 = 120a

a = 3828.706 / 120

a = 31.905 ft/s²

Therefore, the local acceleration due to gravity at that elevation is 31.905 ft/s²

3 0
3 years ago
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