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Marianna [84]
2 years ago
5

Light trucks and vans were mandated what year

Engineering
1 answer:
Archy [21]2 years ago
6 0

Answer: The first nationwide US light duty vehicle emission standards were implemented in 1968, and subsequently reviewed every couple of years. New standards were referred to by the effective model year of the regulation from 1968 to 1987

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Valorant Or Csgo? which is best in your opinion?
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Answer:

valorant valorant valorant is the best

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James River Jewelry is a small jewelry shop. While James River Jewelry does sell typical jewelry purchased form jewelry vendors,
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Answer:

This question is comprising many parts (a to r). That is impossible to answer in one sheet. Following are attached images having answers to most of the parts.

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Solar energy stored in large bodies of water, called solar ponds, is being used to generate electricity. If such a solar power p
fgiga [73]

Answer: 1.137*10^7 Btu/h.

Explanation:

Given data:

Efficiency of the plant = 4.5percent

Net power output of the plant = 150kw

Solution:

The required collection rate

QH = W/n

= 150/0.045 * 0.94782/ 1 /60 */60 Btu/h.

= 3333.333 *3412.152Btu/h.

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3 0
2 years ago
Multiple Choice
12345 [234]

Answer:https://global.oup.com/us/companion.websites/9780199385423/student/ch6/mcq/     just go here

Explanation:

6 0
3 years ago
1. Calculate the battery life in years when a pacemaker has the following characteristics: Battery Ampere-hours = 1.5 Pulse volt
Wittaler [7]

Answer:

battery life in year = 9 years and 48 days

Explanation:

given data

Battery Ampere-hours = 1.5

Pulse voltage = 2 V

Pulse width = 1.5 m sec

Pulse time period = 1 sec

Electrode heart resistance = 150 Ω

Current drain on the battery = 1.25 µA

to find out

battery life in years

solution

we get first here duty cycle that is express as

duty cycle = \frac{width}{period}      ...............1

duty cycle = 1.5 × 10^{-3}

and applied voltage will be

applied voltage = duty energy × voltage    ...........2

applied voltage = 1.5 × 10^{-3} × 2

applied voltage = 3 mV

so current will be

current = \frac{applied\ voltage}{resistance}   ................3

current = \frac{3}{150}

current = 20 µA

so net current will be

net current = 20 - 1.25

net current = 18.75 µA

so battery life will be

battery life = \frac{1.5}{18.75*10^{-6}}

battery life = 80000 hours

battery life in year = \frac{80000}{8760}

battery life in year = 9.13 years

battery life in year = 9 years and 48 days

4 0
3 years ago
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