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sukhopar [10]
3 years ago
5

The formula for the cross sectional area of specimen at the middle is

Engineering
1 answer:
poizon [28]3 years ago
8 0
Times the radius squared !

hope this helps :)))
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Ultimate tensile strength is: (a) The stress at 0.2% strain (b) The stress at the onset of plastic deformation (c) The stress at
MissTica

Answer:

By definition the ultimate tensile strength is the maximum stress in the stress-strain deformation. The stress at 0.2% strain, the stress at the onset of plastic deformation, the stress at the end of the elastic deformation and the stress at the fracture correspond, by definition, to other points of the stress-strain curve.

Explanation:

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What oil specification is used to express the thickness (viscosity) of the oil?​
Marianna [84]

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Viscosity is notated using the common classification “XW-XX”. The number preceding the “W” (winter) rates the oil's flow (viscosity) at zero degrees Fahrenheit (-17.8 degrees Celsius). The lower the number, the less the oil thickens in cold weather.

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2 years ago
Describe the Optical Fiber Network( i need 2 paragraphs, but give me about 5 sentences or like 3)
frez [133]

Answer: Fiber Optic Network Fiber-optic networks have been used for decades to transmit large volumes of traffic across the country. The economics of fiber networks have only recently allowed for connecting the fiber directly to the home, creating a fiber-to-the-home (FTTH) network.

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3 years ago
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What is Maglev Technology?<br> I don't want a copied and pasted answer please.
Levart [38]

Answer:

I do not know much but I looked and read, this I learned I hope this is good

The Maglev is a system of train transportation that uses two sets of magnets

working repel one another when matching poles face each other. Here, both magnetic attraction and repulsion are used to move the train car along the guideway.

Explanation:

Brainliest please

5 0
3 years ago
A vertical piston-cylinder device initially contains 0.2 m3 of air at 20°C. The mass of the piston is such that it maintains a c
Ann [662]

Answer:

Amount of air left in the cylinder=m_{2}=0.357 Kg

The amount of heat transfer=Q=0

Explanation:

Given

Initial pressure=P1=300 KPa

Initial volume=V1=0.2m^{3}

Initial temperature=T_{1}=20 C

Final Volume=V_{2}=0.1 m^{3}

Using gas equation

m_{1}=((P_{1}*V_{1})/(R*T_{1}))

m1==(300*0.2)/(.287*293)

m1=0.714 Kg

Similarly

m2=(P2*V2)/R*T2

m2=(300*0.1)/(0.287*293)

m2=0.357 Kg

Now calculate mass of air left,where me is the mass of air left.

me=m2-m1

me=0.715-0.357

mass of air left=me=0.357 Kg

To find heat transfer we need to apply energy balance equation.

Q=(m_{e}*h_{e})+(m_{2}*h_{2})-(m_{1}*h_{1})

Where me=m1-m2

And as the temperature remains constant,hence the enthalpy also remains constant.

h1=h2=he=h

Q=(me-(m1-m2))*h

me=m1-me

Thus heat transfer=Q=0

6 0
3 years ago
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