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3 years ago

5

The formula for the cross sectional area of specimen at the middle is

1 answer:

poizon [28]3 years ago

8 0

Times the radius squared !

hope this helps :)))

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In a manufacturing process, long aluminum rods of square cross section with d = 25 mm are cooled from an initial temperature of

laiz [17]

Answer:

The time required will be 511 seconds.

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3 years ago

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A piston–cylinder device contains 15 kg of saturated refrigerant-134a vapor at 280kPa. A resistance heater inside the cylinder w

attashe74 [19]

Answer:

18.77 A

Explanation:

To solve this we use the energy balance equation, that is:

$E_{in}-E_{out}=\Delta E_{sys}\\\\Q_{in}+W_{in}+W_{out}=\Delta U\\\\Q_{in}+W_{in}=\Delta U\\\\But\ W_{in}=Voltage(V)*Current(I)*change\ in\ time(\Delta t)=VI\Delta t,\Delta U=m(h_2-h_1)\\\\Given\ that\ m=15kg,V=110\ V,\Delta t=6\ min = (6*60\ s)=360\ s,Q_{in}=20.67\ kJ/kg*15\ kg=310.05\ kJ=310050\ J\\\\From\ table: At\ P_1=280kPa, h_1=249.71\ kJ/kg=249710\ J/kg;At\ P_2=280kPa \ and\ T_1=75^oC,P_2=319.95\ kJ/kg=319950\ J/kg\\\\Substituting:\\\\310500+(110*360*I)=15(319950-249710)\\\\$

$39600I=1053600-310500\\\\39600I=743100\\\\I=18.77\ A$

3 0

3 years ago

hellooooo guyssssddddddsss i was talking to some people help me find them if you are them tell me and tyyyyyyyyyyyyyyyyyyyyyyyyy

mash [69]

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3 years ago

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A company intends to market a new product and it estimates that there is a 20% chance that it will be first in the market

Stells [14]

The EMV - Ending Market Value is given as:
$2,400,000.

<h3>How is the EMV Arrived At?</h3>

The EMV is given as:

BMV x (i + r); Where

BMV is the Beginning Market Value; and

r is the interest rateor percentage given.

Hence the EMV = 2,000,000 x ( 1 + 20%)

= 2,000,000 x 1.2

= $ 2, 400,000.

It is to be noted that the BMV is the Beginning Market Value which is the value of an investment at the start of the business period.

Learn more about Market Value at:

brainly.com/question/1350233

4 0

3 years ago

A unidirectional E-Glass fiber-epoxy composite material contains 61% by volume E-Glass fibers stressed under isostrain condition

zalisa [80]

Answer:

The total load carried by the fiber will be "98%".

Explanation:

The given values are:

$V_{f}=0.61$

$V_{m}=1-V_{f}$

$=1-0.61$

$=0.39$

$E_{f}=10 \ Mpa$

$\sigma_{f}=0.35 \ Mpa$

$E_{m}=0.45 \ Mpa$ , $\sigma_{m}=9\times 10^{-3} \ Mpa$

As we know,

⇒ $E_{e}=fE_{f}+mE_{m}$

On putting the estimated values, we get

⇒ $=0.61\times 10+0.39\times 0.95$

⇒ $=6.27 \ Mpa$

Now,

⇒ $\sigma_{c}=f\sigma_{f}+m\sigma_{m}$

On putting the estimated values, we get

⇒ $=0.61\times 0.35+0.39\times 0.009$

⇒ $=0.217 \ Mpa$

Therefore,

The load carried by fiber,

$=\frac{f\sigma_{f}}{\sigma_{c}}$

$=\frac{0.35\times 0.61}{0.217}$

$=0.98$ i.e., 98%

4 0

4 years ago