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nasty-shy [4]
3 years ago
9

ASAP need physics help please:)

Physics
1 answer:
boyakko [2]3 years ago
3 0

Answer:

plantation of force of the earth acting on 15 kg of object on free fall the acceleration of free fall said about it now it is year 15 kg then it becomes 1.53 Newton

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Identify the areas on the image where the force of repulsion is the least.​
aalyn [17]

Answer:

The central blue square in between the lower pair of magnet has the least force of repulsion.

Explanation:

We can explain this using the dual nature of magnets.

Each magnet must have two poles namely:

-North pole

-South pole

We assume that the magnetic lines of forces enters from south pole and leaves from the north pole.

When brought together, like poles repel each other while opposite poles attract each other.

In the picture, the lower two magnets have opposite poles facing each other, hence the force of repulsion is minimum there and the force of attraction is maximum.

4 0
3 years ago
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An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after
KatRina [158]

Answer:

E = kQs/r.r

Explanation:

Where E is the magnitude of electric field...

k is called Columb's Constant. It has a value of 8.99 x 109 N m2/C2.

Qs is the magnitude of the source charge...

and r is the magnitude of distance between source and target...

(When electron comes to rest Δt the magnitude of Electric field E become zero momentarily but later achieves the maximum value...)

5 0
3 years ago
Question 2: The number of protons plus the number of neutrons in an atom is equal to its
Reika [66]
Answer B) the mass number
6 0
3 years ago
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1. what factor does work depends on?<br>2. what factor does power depends on? ​
Harrizon [31]
1.motivation 2. ????
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2 years ago
At which point on this electric field will a test charge show the maximum strength?
Juli2301 [7.4K]

Answer:

A

Explanation:

The figure shows the electric field produced by a spherical charge distribution - this is a radial field, whose strength decreases as the inverse of the square of the distance from the centre of the charge:

E\propto \frac{1}{r^2}

More precisely, the strength of the field at a distance r from the centre of the sphere is

E=k\frac{Q}{r^2}

where k is the Coulomb's constant and Q is the charge on the sphere.

From the equation, we see that the field strength decreases as we move away from the sphere: therefore, the strength is maximum for the point closest to the sphere, which is point A.

This can also be seen from the density of field lines: in fact, the closer the field lines, the stronger the field. Point A is the point where the lines have highest density, therefore it is also the point where the field is strongest.

8 0
3 years ago
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