Cover your cough
Wash your hands
Keep a clean space
Avoid smoking
Stay active
Hope this helps :)
Answer:
0.2286 m, 0.686 m and 1,143 m
therefore we see that there is respect even where the intensity is minimal
Explanation:
Destructive interference to the two speakers is described by the expression
Δr = (2n +1) λ/2
where r is the distance, λ the wavelength and n an integer indicating the order of the interference
let's locate the origin on the left speaker
let's find the wavelength with the equation
v = λ f
λ = v / f
we substitute
Δr = (2n + 1) v / 2f
let's calculate for difference values of n
Δr = (2n +1) 343/(2 750)
Δr = (2n + 1) 0.2286
we locate the different values for a minimum of interim
n Δr (m)
0 0.2286
1 0.686
2 1,143
therefore we see that there is respect even where the intensity is minimal
Answer:
Random Motion is a motion in which an object didn't go in a straight manner, for ex: zig zag lines, curved, etc.
Explanation:
In this case, the object is thrown upwards from the building. Therefore, it first achieves some height before its starts dropping.
Now, when going upwards
v^2 = u^2 - 2gs
Where,
v = final velocity
u = initial velocity
g = gravitational acceleration
s = height achieved from the top of he bulding
Using the values given;
v = 0 (comes into rest before it starts dropping)
u = 21.82 mi/h = 32 ft/s
g = 9.81 m/s^2 = 32.174 ft/s^2
Then,
0^2 = 32^2 - 2*32.174*s
32^2 = 2*32.174*s
s = (32^2)/(2*32.174) = 15.91 ft
After achieving that height, it starts to drop from rest to maximum velocity when it hits the ground.
Applying the same formula;
v^2 = u^2 + 2gs
Where;
v = velocity when it hits the ground
u = initial velocity, 0 ft/s as it starts from rest
s = 15.91+1.6*10^2 = 15.91+160 = 175.91 ft
Therefore,
v^2 = 0^2 + 2*32.174*175.91
v^2 = 11319.68
v = Sqrt (11319.68) = 106.39 ft/s ≈ 32.43 m/s moving downwards.
Answer:
B. The force would be the same in both cases.
Explanation:
As we know that the force is defined as the rate of change in momentum of the system
So here we will have
so in both the cases the change in the momentum of the car will be same
also the time interval is given same in both the cases
so here we can say
so force will be same on the car in both the cases
