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IrinaK [193]
3 years ago
14

A boat has a propulsion system that consists of a pump that sucks water at the bow and presses it on the stern. All tubes are 5

cm in diameter and the outlet flow is 50 L/s.
Calculate the propulsion force at the moment of departure, that is, with the boat at rest. The pressure at the inlets and outlets is assumed to be practically atmospheric (water density = 1000 Kg /m3).
Physics
1 answer:
Phoenix [80]3 years ago
7 0

Answer:

The propulsion force at the moment of departure, is 49 N  

Explanation:

Given;

diameter of tubes = 5 cm = 0.05 m

volumetric flow rate, V = 50 L/s = 0.005 m³/s

density of water, ρ = 1000 Kg /m³

hydraulic / propulsion force, F = ρVg

where;

ρ is the density of the fluid (water)

V is the volumetric flow rate of water

g is acceleration due to gravity

propulsion force, F = ρVg

propulsion force, F = 1000 x 0.005 x 9.8

propulsion force, F = 49 N      

Therefore, the propulsion force at the moment of departure, is 49 N  

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A 0.12 kg body undergoes simple harmonic motion of amplitude 8.5 cm and period 0.20 s. (a) What is themagnitude of the maximum f
Neporo4naja [7]

Answer:

a)F=698.83 N

b)K=8221.56 N/m

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T=\dfrac{2\pi}{\omega}

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