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IrinaK [193]
4 years ago
14

A boat has a propulsion system that consists of a pump that sucks water at the bow and presses it on the stern. All tubes are 5

cm in diameter and the outlet flow is 50 L/s.
Calculate the propulsion force at the moment of departure, that is, with the boat at rest. The pressure at the inlets and outlets is assumed to be practically atmospheric (water density = 1000 Kg /m3).
Physics
1 answer:
Phoenix [80]4 years ago
7 0

Answer:

The propulsion force at the moment of departure, is 49 N  

Explanation:

Given;

diameter of tubes = 5 cm = 0.05 m

volumetric flow rate, V = 50 L/s = 0.005 m³/s

density of water, ρ = 1000 Kg /m³

hydraulic / propulsion force, F = ρVg

where;

ρ is the density of the fluid (water)

V is the volumetric flow rate of water

g is acceleration due to gravity

propulsion force, F = ρVg

propulsion force, F = 1000 x 0.005 x 9.8

propulsion force, F = 49 N      

Therefore, the propulsion force at the moment of departure, is 49 N  

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It is important for scientists to use the same scientific method and consistent measurement units in order to get the correct value while analayzing.

<h3>What is matter?</h3>

The matter has volume and space occupied.

When conceivable the researcher endeavors to test his speculations via painstakingly planned and controlled tests that will yield quantitative instead of subjective outcomes.

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2 years ago
PLEASE HELP, THANK YOU!.. :)
Firlakuza [10]

Answer:

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^{234}U  =>  ^{230} Th + ^{4}He

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^{234} U  => ^{226}Ra + 2( ^{4} He)

8 0
3 years ago
A car is moving at 5 m/s. 2 seconds later, it is traveling at 17 m/s. How far did the car go?
vekshin1

Answer:

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Explanation:

3 0
3 years ago
A bridge that was 5.0 m long has been washed out by the rain several days ago. How fast must a car be going to successfully jump
amid [387]

Answer:

Speed, v = 7.83 m/s

Explanation:

It is given that,

Length of the bridge, l = 5 m

The road on the far side is 2.0 m lower than the road on this side, x = 2 m

The horizontal distance covered by the car is 5 meters and the vertical distance covered by the car is 2 meters.

Initial speed of the car, u = 0

Let t is the time taken by the car . Using the second equation of motion as :

For vertical distance :

s=ut+\dfrac{1}{2}gt^2

t=\sqrt{\dfrac{2\times 2}{9.8}}=0.638\ s

Let v is the velocity to jump the stream. It is given by :

Horizontal distance, d = 5 m

v=\dfrac{5\ m}{0.638\ s}

v = 7.83 m/s

So, the car should travel with a speed of 7.83 m/s. Hence, this is the required solution.

8 0
4 years ago
A 3 kg ball rolls at 2m/s does this system favor kinetic energy or potential energy?
MissTica

Answer:

Kinetic energy

Explanation:

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E = K +U

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U = Potential energy

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5 0
3 years ago
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