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3 years ago

PLS SOMEONE HELP QUICK

Physics

2 answers:

SVETLANKA909090 [29]3 years ago

6 0

Answer:

the rates of rock formation are similar. i could be wrong tho.....

Explanation:

valentinak56 [21]3 years ago

5 0

I believe it is B that the sedimentary rock formation was similar

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The air around a pool and the water in the pool receive equal amounts of energy from the sun. Why does the air experience a grea

labwork [276]

Answer:

Explanation:

4 0

3 years ago

Electrons are ejected from a metallic surface with speeds of up to 4.60 3 105 m/s when light with a wavelength of 625 nm is used

Darya [45]

Complete question:

Electrons are ejected from a metallic surface with speeds ranging up to 4.60 x10⁵ m/s when light with a wavelength of 625nm is used. (a) What is the work function of the surface? (b) What is the cutoff frequency for this surface?

Answer:

Part(a) The work function of the surface is 22.177 x 10⁻²⁰ J = 1.384 eV

Part(b) The cutoff frequency for this surface is 3.347 x 10¹⁴ Hz

Explanation:

The kinetic energy (KE) of the emitted photon:

KE = 0.5mv²

m is mass of electron = 9.1 X 10⁻³¹ kg

KE = 0.5 * 9.1 X 10⁻³¹ * (460000)² = 9.628 X 10⁻²⁰ J

in eV = 9.628 X 10⁻²⁰ J x 6.242 X 10¹⁸ ev = 0.601 eV

The photon energy of the incoming radiation:

E = hf = hc/λ

c is speed of light (photon) = 3 x 10⁸

h is Planck's constant = 6.626 × 10⁻³⁴ J.s

E = (6.626 × 10⁻³⁴ *3 x 10⁸) /(625 X 10⁻⁹)

E = 31.805 X 10⁻²⁰ J

in eV = 31.805 X 10⁻²⁰ J x 6.242 X 10¹⁸ ev = 1.985 eV

Part (a) the work function of the surface

KE = hf - W

where;

W is work function

W = hf - KE

W = 31.805 X 10⁻²⁰ J - 9.628 X 10⁻²⁰ J = 22.177 x 10⁻²⁰ J

in eV = 22.177 x 10⁻²⁰ J x 6.242 X 10¹⁸ ev = 1.384 eV

Part(b) the cutoff frequency for this surface

W =hf

f = W/h

f = (22.177 x 10⁻²⁰ J)/(6.626 × 10⁻³⁴ J.s)

f = 3.347 x 10¹⁴ Hz

8 0

3 years ago

A smooth wooden block is placed on a smooth wooden tabletop. You find that you must exert a force of 22.0 N to keep this 7.00 kg

xxMikexx [17]

Answer:

B . 68.7 N

Explanation:

Given in the question that;

Force = 22 N

Mass = 7.0 kg

Velocity = 4.0 m/s

Gravitational force is the weight of wooden block , calculated as mass times acceleration due to gravity.

F= m* a

F= 7 * 9.81

F= 68.67 N

F= 68.7 N

7 0

3 years ago

PLEASE HELP ME IN THIS QUESTION!!!

kirill115 [55]

Answer:

Acceleration is 8.45 and the tension is 2.775

Explanation:

Lets apply the equation F=ma for vertical block,

5-T= 0.5a

foe the frictional force acting on the object,

f=0.11×5 (consider equation no.1)

=0.55N

Applying F=ma for the block which is on surface,

T-0.55=0.5a (consider as equation no.2)

no.1=no.2

5.55=2T

T=2.775

by equation no.1,

4.225=0.5a

a=8.45

8 0

3 years ago

Consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric field and the

MissTica

Answer:

V = 10581.59 V

Explanation:

To solve this problem, we have to take into the relation between the kinetic energy of an electron and the energy generated by the potential difference of an electric field. This relation is given by

$E_{k} = E_{V}$

$\frac{1}{2}mv^{2} = eV$

where m is the mass of the electron, v is the velocity of the electron, e is the electric charge and V is the potential difference that accelerated the electron.

By taking V from the last expression we have:

$V = \frac{mv^{2}}{2e} = \frac{(9.1*10^{-31} )(6.1*10^{7})^{2}}{2*(-1.6*10^{-19})}} = 10581.59 V$

where we have taken that

me = 9.1*10^(-31) Kg

e = -1.6*10^(-19) C

v = 6.1*10^(7)

I hope this is useful for you

Regards

6 0

4 years ago