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3 years ago

Qee-himr-uxa disturb our class

Chemistry

2 answers:

zubka84 [21]3 years ago

7 0

Answer:

thanks for the point

Explanation:

have a good day please mark me as brain list ☺️

luda_lava [24]3 years ago

7 0

Answer:

thanks for freeeee pöints..!

Have a nice day ahead..!

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Which following statements is true?

Aleksandr-060686 [28]

Answer:

first one

Explanation:

hope this helps

8 0

3 years ago

Read 2 more answers

The molar enthalpy of vaporization of boron tribromide is 30.5 kj/mol, and its normal boiling point is 91°c. what is the vapor p

adell [148]

To answer this question, we will use the following equation:
ln(P2/P1) = (∆Hvap/R)*((1/T1) - (1/T2))

Now we examine the givens of the problem and transform to standard units if required:
∆Hvap = 30.5 kJ/mol
R is a constant = 8.314 x 10^-3 kJ K^-1 mol^-1
T1 = 91 celcius = 91 + 273= 364 Kelvin
T2 = 20 celcius = 20 + 273 = 293 k3lvin
P1 is the standard atmospheric pressure = 760 mmHg
P2 is the value to be calculated

Substitute with these values in the equation:
ln(P2/760) = (30.5 / 8.314 x 10^-3) x ((1 / 364) - (1 / 293))
ln(P2/760) = - 2.4662 (Take the exponential both sides to eliminate the ln)
P2 / 760 = e^(-2.4462) = 0.0866
P2 = 0.0866 x 760 = 65.816 mmHg

5 0

4 years ago

Use the drop-down menus to identify the electromagnetic waves.

mezya [45]

Answer:

Label A - Radio waves

Label C - Infrared

Label D - Visible light

Label G- Gamma rays

Explanation:

Electromagnetic spectrum is an arrangement of electromagnetic waves in order of their varying frequencies and wavelengths,
Radiowaves have the highest wavelength and lowest frequency while the gamma rays have the lowest wavelength and the highest frequency.
In order of increasing wavelength and decreasing frequency the electromagnetic waves are; Gamma rays, X-rays, U.V light, Visible light, infrared waves, microwaves, and Radio waves.

6 0

3 years ago

Read 2 more answers

consider the reaction between calcium oxide and carbon dioxide: cao ( s ) + co 2 ( g ) → caco 3 ( s ) a chemist allows 14.4 g of

MakcuM [25]

Answer:

CaO is the limiting reagent

Theoritical yield = 25.71 g

% Yield = 75.44%

Explanation:

1 mole = Molar mass of the substance

Molar Mass of CaO = 56 g/mol

Molar Mass of CaCO3 = 100 g/mol

Molar mass of CO2 = 44 g/mol

The balanced Equation is :

$CaO + CO_{2}\rightarrow CaCO_{3}$

1 mole of CaO reacts with = 1 mole of CO2

56 g of CaO reacts with = 44 g of CO2

1 g of CaO reacts with =

$\frac{44}{56}$

= 0.785 g of CO2

So,

14.4 g of CaO must react with = (14.4 x 0.785) g of CO2

= 11.31 g of CO2

Needed = 11.31 g

Available CO2 = 13.8 g (given)

So CO2 is in excess , hence CaO is the limiting reagent and product will produce from 14.4 g of CaO

$CaO + CO_{2}\rightarrow CaCO_{3}$

1 mole of CaO will produce 1 mole pf CaCO3

56 g of CaO produce = 100 g of CaCO3

1 g of CaO produce =

$\frac{100}{56}$

= 1.785 g of CaCO3

14.4 g of CaO will produce = (1.785 x 14.4) g of CaCO3

= 25.71 g of CaCO3

Theoritical Yield of CaCO3 = 25.71 g

Actual yield = 19.4 g

Percent Yield =

$\frac{Actual\ yield}{Theoritical\ yield}\times 100$

$\frac{19.4}{25.71}\times 100$

= 75.44 %

6 0

3 years ago

Which equation is used to help form the combined gas law?

kkurt [141]

Answer:

The ideal gas equation

Explanation:

The ideal gas equation is derived from the combination of three gas laws:

Boyle's law
Charles's law
Avogadro's law.

The ideal gas law is expressed mathematically as: PV=nRT where:

P is pressure

V is volume

n is the number of moles

R is the ideal gas law

T is temperature.

To obtain the combined gas law, we assume that n=1 and this gives:

$\frac{PV}{T}$ = R

Therefore:

$\frac{P_{1} V_{1} }{T_{1} }$ = $\frac{P_{2} V_{2} }{T_{2} }$

5 0

3 years ago

Qee-himr-uxa disturb our class​

Qee-himr-uxa disturb our class