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jekas [21]
3 years ago
11

Qee-himr-uxa disturb our class​

Chemistry
2 answers:
zubka84 [21]3 years ago
7 0

Answer:

thanks for the point

Explanation:

have a good day please mark me as brain list ☺️

luda_lava [24]3 years ago
7 0

Answer:

thanks for freeeee pöints..!

Have a nice day ahead..!

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arrange the liquids in the order of density from the highest to the lowest liquids:brine,kerosene and water​
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A 3.00-L flask is filled with gaseous ammonia, NH3. The gas pressure measured at 27.0 ∘C is 2.55 atm . Assuming ideal gas behavi
Whitepunk [10]

Answer : The mass of ammonia present in the flask in three significant figures are, 5.28 grams.

Solution :

Using ideal gas equation,

PV=nRT\\\\PV=\frac{w}{M}\times RT

where,

n = number of moles of gas

w = mass of ammonia gas  = ?

P = pressure of the ammonia gas = 2.55 atm

T = temperature of the ammonia gas = 27^oC=273+27=300K

M = molar mass of ammonia gas = 17 g/mole

R = gas constant = 0.0821 L.atm/mole.K

V = volume of ammonia gas = 3.00 L

Now put all the given values in the above equation, we get the mass of ammonia gas.

(2.55atm)\times (3.00L)=\frac{w}{17g/mole}\times (0.0821L.atm/mole.K)\times (300K)

w=5.28g

Therefore, the mass of ammonia present in the flask in three significant figures are, 5.28 grams.

8 0
4 years ago
WILL GIVE BRAINLIEST ANSWER ASAP
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The answer is b. Food chains are extremely fragile. In many occasions, the health of a species will depend on the survival of the species right under. At the end, we realize that the chain is quite fragile because everyone depends on each other, but not every species are strong enough to survive the change in their environment.

6 0
3 years ago
Determine the specific heat of a 70 g sample of material that absorbed 96 J as it was heated from 293 K to 313 K
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This problem is providing us with the mass (70 g), absorbed heat (96 J) and initial and final temperatures (293 K and 313 K, respectively) so the specific heat of the material is required and found to be 0.0686 J/(g*K) as shown below:

<h3>Calorimetry:</h3>

In chemistry, we can go over calorimetry by writing the following relationship among heat, mass, specific heat and temperature change:

Q=mC(T_f-T_i)

Thus, one can get the specific heat by solving for C in the previous equation:

C=\frac{Q}{m(T_f-T_i)}

Hence, we can plug in the given data to obtain:

C=\frac{96J}{70g(313K-293K)}\\ \\C=0.0686\frac{J}{g*K}

Learn more about calorimetry: brainly.com/question/1407669

5 0
2 years ago
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