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4 years ago

3. Technician A says passive permanent

Engineering

1 answer:

Angelina_Jolie [31]4 years ago

6 0

Answer:

Both technician A and B

Explanation:

Passive permanent magnet ABS wheel speed sensors produce an A/C voltage signal. Wheel speed sensors are a necessary ABS component and sensor input. It is used to inform the ABS control module of rotational wheel speed. A passive sensor creates an AC signal that changes frequency as the wheel changes speed. Moreover, input from wheel speed sensors are used for anti- lock brake, electronic traction control, and electronic stability control systems. Therefore, both technicians are correct.

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A square plate of titanium is 12cm along the top, 12cm on the right side, and 5mm thick. A normal tensile force of 15kN is appli

Scrat [10]

Answer:

$X_t=2.17391304*10^{-4}$

$X_r=2.89855072*10^{-4}$

$e_t=0.0026$

$e_r=0.0035$

Explanation:

From the question we are told that:

Dimension $12*12$

Thickness $l_t=5mm=5*10^-3$

Normal tensile force on top side $F_t= 15kN$

Normal tensile force on right side $F_r= 20kN$

Elastic modulus, $E=115Gpap=>115*10^9$

Generally the equation for Normal Strain X is mathematically given by

$X=\frac{Force}{Area*E}$

Therefore

For Top

$X_t=\frac{Force_t}{Area*E}$

Where

$Area=L*B*T$

$Area=12*10^{-2}*5*10^{-3}$

$Area=6*10^{-4}$

$X_t=\frac{15*10^3}{6*10^{-4}*115*10^9}$

$X_t=2.17391304*10^{-4}$

For Right side $X_r=\frac{Force_r}{Area*E}$

Where

Area=L*B*T

$Area=12*10^{-2}*5*10^{-3}$

$Area=6*10^{-4}$

$X_r=2.89855072*10^{-4}$

Generally the equation for elongation is mathematically given by

$e=strain *12$

For top

$e_t=2.17391304*10^{-4}*12$

$e_t=0.0026$

For Right

$e_r=2.89855072*10^{-4} *12$

$e_r=0.0035$

5 0

3 years ago

What is the governing ratio for thin walled cylinders?

Ann [662]

Answer:

The governing ratio for thin walled cylinders is 10 if you use the radius. So if you divide the cylinder´s radius by its thickness and your result is more than 10, then you can use the thin walled cylinder stress formulas, in other words:

if $\frac{radius}{thickness} >10$ then you have a thin walled cylinder

or using the diameter:

if $\frac{diameter}{thickness} >20$ then you have a thin walled cylinder

3 0

3 years ago

Given the following phasors and the information related to the frequency of that phasor, provide the corresponding time-domain r

Evgesh-ka [11]

Answer:

Explanation:

In Engineering and Physics a Phasor That is a portmanteau of phase vector, is a complex number that represents a sinusoidal function whose Amplitude (A), Angular Frequency (ω), and Initial Phase (θ) are Time-invariant.

For the step by step solution to the question you asked, go through the attached documents.

4 0

3 years ago

Write the definitions for engineering stress, true stress, engineering strain, and true strain for loading along a single axis.

shusha [124]

Answer and Explanation:

Engineering Stress of a material is defined as the applied load or force divided by the original cross sectional Area of the material.

σ(engineering) = F/(Ao)

True Stress is defined as the applied load or force divided by the actual cross-sectional area (the changing area with respect to time) of the material at that point in time. It's an instantaneous stress.

σ(true) = F/A

Engineering strain is a measure of how much a material deforms under a particular load. It is the amount of deformation in the direction of the applied force divided by the initial length of the material.

ε(engineering) = Δl/lo

True Strain measures instantaneous deformation. It is obtained mathematically by integrating strain over small time periods and summing them up. Hence,

ε(true) = In (lf/lo)

The calculations,

First step, 10m to 10.1m, Δl = 0.1m, lf = 10.1m, lo = 10m

ε(engineering) = 0.1/10 = 0.01

ε(true) = In (10.1/10) = 0.00995

Second step, 10.1m to 10.2m, Δl = 0.1m, lf = 10.2m, lo = 10.1m

ε(engineering) = 0.1/10.1 = 0.0099

ε(true) = In (10.2/10.1) = 0.00985

Overall, 10m to 10.2m, Δl = 0.2m, lf = 10.2m, lo = 10m

ε(engineering) = 0.2/10 = 0.02

ε(true) = In (10.2/10) = 0.0198

QED!

5 0

3 years ago

Read the first paragraph of the article.

Paladinen [302]

Answer:

i think it is A, i could not really understand your question.

Explanation:

just a question

(wheres the article?)

5 0

3 years ago