Answer:
6.5 × 10¹⁵/ cm³
Explanation:
Thinking process:
The relation ![N_{o} = N_{i} * \frac{E_{f}-E_{i} }{KT}](https://tex.z-dn.net/?f=N_%7Bo%7D%20%3D%20N_%7Bi%7D%20%2A%20%5Cfrac%7BE_%7Bf%7D-E_%7Bi%7D%20%20%7D%7BKT%7D)
With the expression Ef - Ei = 0.36 × 1.6 × 10⁻¹⁹
and ni = 1.5 × 10¹⁰
Temperature, T = 300 K
K = 1.38 × 10⁻²³
This generates N₀ = 1.654 × 10¹⁶ per cube
Now, there are 10¹⁶ per cubic centimeter
Hence, ![N_{d} = 1.65*10^{16} - 10^{16} \\ = 6.5 * 10^{15} per cm cube](https://tex.z-dn.net/?f=N_%7Bd%7D%20%20%3D%201.65%2A10%5E%7B16%7D%20%20-%2010%5E%7B16%7D%20%5C%5C%20%20%20%20%20%20%20%20%20%20%20%3D%206.5%20%2A%2010%5E%7B15%7D%20per%20cm%20cube)
Answer:
The right solution is "2625 kN".
Explanation:
According to the question,
The average pressure will be:
= ![density\times g\times \frac{h}{2}](https://tex.z-dn.net/?f=density%5Ctimes%20g%5Ctimes%20%5Cfrac%7Bh%7D%7B2%7D)
By putting values, we get
= ![1000\times 9.8\times \frac{12.2}{2}](https://tex.z-dn.net/?f=1000%5Ctimes%209.8%5Ctimes%20%5Cfrac%7B12.2%7D%7B2%7D)
= ![1000\times 9.8\times 6.1](https://tex.z-dn.net/?f=1000%5Ctimes%209.8%5Ctimes%206.1)
= ![59780](https://tex.z-dn.net/?f=59780)
hence,
The average force will be:
= ![Pressure\times Area](https://tex.z-dn.net/?f=Pressure%5Ctimes%20Area)
= ![59780\times 3.6\times 12.2](https://tex.z-dn.net/?f=59780%5Ctimes%203.6%5Ctimes%2012.2)
= ![2625537 \ N](https://tex.z-dn.net/?f=2625537%20%5C%20N)
Or,
= ![2625 \ kN](https://tex.z-dn.net/?f=2625%20%5C%20kN)
Answer:
i think yes it could make the color go lighter
Explanation:
No clue sorry man I would help but I need help too
Answer:
Check the explanation
Explanation:
class LanguageHelper:
language=set()
#Constructor
def __init__(self, words):
for w in words:
self.language.add(w)
def __contains__(self,query):
return query in self.language
def getSuggestionns(self,query):
matches = []
for string in self.language:
if string.lower().startswith(query) or query.lower().startswith(string) or query.lower() in string.lower():
matches.append(string)
return matches
lh = LanguageHelper(["how","Hi","What","Hisa"])
print('how' in lh)
print(lh.getSuggestionns('hi'))
===========================================
OUTPUT:-
==================
True
['Hisa', 'Hi']
====