Answer:
Explanation:
Take a look at the balanced chemical equation that describes this reaction
Cu
(
s
)
+
2
AgNO
3
(
a
q
)
→
Cu
(
NO
3
)
2
(
a
q
)
+
2
Ag
(
s
)
Notice that the chemical equation provides you with information about how many moles of each chemical species takes part in this reaction.
More specifically, you know that
1
mole of solid copper will react with
2
moles of silver nitrate to produce
1
mole of aqueous copper(II) nitrate and
2
moles of solid silver.
So, assuming that you have enough silver nitrate available to allow for all the sample of copper to react, you can expect the reaction to produce twice as many moles of solid silver than you have moles of solid copper taking part in the reaction.
Use the molar mass of copper to calculate how many moles you have in your sample
1.00
g
⋅
1 mole Cu
63.546
g
=
0.01574 moles Cu
According to the aforementioned mole ratio, the reaction will produce
0.01574
moles Cu
⋅
2
a
moles Ag
1
mole Cu
=
0.03148 moles Ag
Finally, use the molar mass of silver to convert the number of moles to grams
Answer:
a. K = [H+][NO2-]/[HNO2]
Explanation:
The computation of the expression of the equilibrium constant is shown below:
Given that the weak acid is HNO_2 that exist in the solution that aqueous
The dissociation equation of 
Now
Acidionization constant i.e.
![k_a = \frac{[NO_{2}^{-}][H^{+}]}{HNO_{2}}](https://tex.z-dn.net/?f=k_a%20%3D%20%5Cfrac%7B%5BNO_%7B2%7D%5E%7B-%7D%5D%5BH%5E%7B%2B%7D%5D%7D%7BHNO_%7B2%7D%7D)
Therefore the correct option is a.
Hence, the same is to be considered
Answer : The density of iron is, 7.8 g/mL
Explanation : Given,
Mass of iron = 4.7 g
Volume of water = 27.10 mL
Volume of water and iron = 27.70 mL
First we have to calculate the volume of iron.
Volume of iron = Volume of water and iron - Volume of water
Volume of iron = 27.70 mL - 27.10 mL
Volume of iron = 0.6 mL
Now we have to calculate the density of iron.
Now put all the given values in this expression, we get:
Thus, the density of iron is, 7.8 g/mL
Dmitri Mendeleev is the answer
Calcium chloride contains only one calcium and 2 chloride atom thus it's ionic formula would be CaCl2.
