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2 years ago

A 20 ml solution of sugar with a concentration of

Chemistry

1 answer:

ki77a [65]2 years ago

6 0

Answer:

M₂ = 0.16 M

Explanation:

Given data:

Initial volume of solution = 20 mL

Initial concentration = 1.0 M

Final volume = 120 mL

Final/new concentration = ?

Solution:

Formula:

M₁V₁ = M₂V₂

by putting values,

1.0 M × 20 mL = M₂ × 120 mL

M₂ = 1.0 M × 20 mL / 120 mL

M₂ = 20 M.mL /120 mL

M₂ = 0.16 M

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Explanation:

The oxidation number of Ni is +4

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2 years ago

How does a catalyst increase the rate of a reaction?

Norma-Jean [14]

Answer:

C) It provides a lower activation energy for the reaction is the correct answer.

Explanation:

A catalyst increases the rate of the chemical reaction by lowering the activation energy for a reaction.

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2 years ago

Ultraviolet radiation and radiation of shorter wavelengths can damage biological molecules because they carry enough energy to b

Alja [10]

Answer:

439.7nm

Explanation:

Energy of a quantum can be calculated using below formula

E=hv...........eqn(1)

But v=λ/ c .........eqn(2)

If we substitute eqn(2) into eqn(1) we have

E= hc/(λ)

Where E= energy

h= Plank's constant= 6.62607004 × 10-34 m2 kg / s

c= speed of light

c= 2.998 × 10^8 m/s

λ= wavelength= ?

But the energy was given in Kj , it must be converted to Kj/ photon for unit consistency.

Energy E= 272 kJ/mol × 1mol/6.02× 10^23

Energy= 451.83× 10^-24 Kj/ photon

E= hc/(λ)...........eqn(1)

If we make λ subject of the formula

λ= hc/E

Then substitute the values we have

λ= [(6.626 × 10^-34) × (2.998 × 10^8)]/451.83× 10^-24

λ=(0.00043965) × (1Kj/1000J) × (10^9nm/1m)

λ=439.7nm

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4 0

2 years ago

(06.04 HC)

Ksju [112]

The mass of sodium chloride at the two parts are mathematically given as

m=10,688.18g
mass of Nacl(m)=39.15g

<h3>What is the mass of sodium chloride that can react with the same volume of fluorine gas at STP?</h3>

Generally, the equation for ideal gas is mathematically given as

PV=nRT

Where the chemical equation is

F2 + 2NaCl → Cl2 + 2NaF

Therefore

1.50x15=m/M *(1.50*0.0821)

1-50 x 15=m/58.5 *(1.50*0.0821)

m=10,688.18g

Part 2

PV=m'/MRT

1*15=m'/58.5*0.0821*273

m'=39.15g

mass of Nacl(m)=m'=39.15g