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Aleksandr [31]
3 years ago
15

Which element combination(s) would result in electrons being shared?

Chemistry
2 answers:
Likurg_2 [28]3 years ago
5 0
Correct option is c) oxygen and hydrogen.... like in <u><em>H2O .. </em></u><em> </em> there is covalent bond due to sharing of electrons ...<em />
Olin [163]3 years ago
5 0

Explanation:

Atoms that share electrons with each other tend to form a covalent bond. Whereas atoms that show transfer of electrons from one atom to another tend to form an ionic bond.

Sodium has atomic number 11 and oxygen has atomic number 8. In order to become stabilized, sodium needs to lose one electron whereas oxygen needs to gain two electrons. So, two sodium atoms will combine with one atom of oxygen. This will form an ionic bond between sodium and oxygen atom.

Carbon has atomic number 4 and fluorine has atomic number 9. Therefore, both of them will share electrons in order to become stabilized. Thus, they will form a covalent bond.

Oxygen atom has atomic number 8 and hydrogen has atomic number 1. Therefore, both of them will share electrons but due to difference in electronegativity of both hydrogen and oxygen they will result in the formation of a polar covalent bond.

Aluminium has atomic number 13 and chlorine has atomic number 17. So, aluminium will donate or transfer its valence electron to chlorine atom. Therefore, it will also form an ionic bond.

Thus, we can conclude that carbon (C) and fluorine (F) and oxygen (O) and hydrogen (H) are the combination(s) that would result in sharing of electrons.

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(1) breaking a pencil (2) rusting of iron

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3 years ago
Salt is poured from a container at 10 cm³ s-¹ and it formed a conical pile whose height at any time is 1/5 the radius of the abo
Romashka-Z-Leto [24]

Answer:

\displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}

Explanation:

Volume of a cone:

  • \displaystyle V=\frac{1}{3} \pi r^2 h

We have \displaystyle \frac{dV}{dt} = \frac{10 \ cm^3}{sec} and we want to find \displaystyle \frac{dh}{dt} \Biggr | _{h\ =\ 6}= \ ? when the height is 2 cm.

We can see in our equation for the volume of a cone that we have three variables: V, r, and h.

Since we only have dV/dt and dh/dt, we can rewrite the equation in terms of h only.

We are given that the height of the cone is 1/5 the radius at any given time, 1/5r, so we can write this as r = 5h.

Plug this value for r into the volume formula:

  • \displaystyle V =\frac{1}{3} \pi (5h)^2 h  
  • \displaystyle V =\frac{1}{3} \pi \ 25h^3

Differentiate this equation with respect to time t.

  • \displaystyle \frac{dV}{dt}  =\frac{25}{3} \pi \ 3h^2 \ \frac{dh}{dt}
  • \displaystyle \frac{dV}{dt}  =25 \pi h^2 \ \frac{dh}{dt}

Plug known values into the equation and solve for dh/dt.

  • \displaystyle 10 = 25 \pi (2)^2  \ \frac{dh}{dt}
  • \displaystyle 10 = 100 \pi  \ \frac{dh}{dt}  

Divide both sides by 100π to solve for dh/dt.

  • \displaystyle \frac{10}{100 \pi} = \frac{dh}{dt}
  • \displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}

The height of the cone is increasing at a rate of 1/10π cm per second.

7 0
3 years ago
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