Question

A chemist prepares a solution of silver(II) oxide by measuring out of silver(II) oxide into a volumetric flask and filling the flask to the mark with water. Calculate the concentration in of the chemist's silver(II) oxide solution. Round your answer to significant digits.

Answer 1

Answer:

$M=7.3x10^{-9}\frac{mol}{L}$

Explanation:

Hello!

In this case, since the values are not given in the question you asked, we are going to use a dataset found on ethernet for this problem, however, if you were given with different values you can follow the exact procedure with those you have.

In such a way, we consider 0.0011 μmol of silver oxide in a 150-mL volumetric flask until the mark, which means that the volume of the solution is 150 mL, in such way, since the molarity is defined by:

$M=\frac{n_{solute}}{V_{solution}}$

In units of mol/L we need to convert from μmol to mol as shown below:

$n=0.0011\mu mol*\frac{1mol}{1x10^6\mu mol} =1.1x10^{-9}mol$

Next the volume in liters is:

$V=150 mL*\frac{1L}{1000mL} =0.150L$

Thus, the concentration in mol/L turns out:

$M=\frac{1.1x10^{-9}mol}{0.150L}\\\\M=7.3x10^{-9}\frac{mol}{L}$

Best regards!