Use the periodic table in the tools bar to answer these questions. How many moles of AgNO3 are present in 1.50 L of a 0.050 M so

Question

3 years ago

5

lution?

2 answers:

IgorC [24] · Answer 1 · 2022-04-02T01:44:23+03:00

IgorC [24]3 years ago

4 0

M= moles de soluto / litros de solucion
moles de soluto = M. litros de solucion

Moles de soluto = 0.050 M x 1.50 L = 0.075 moles de AgNo3

mixer [17] · Answer 2 · 2022-04-02T03:05:09+03:00

mixer [17]3 years ago

3 0

m = Solute moles/liters solution moles of solute =

m. Liters of solution moles of solute = 0050 m x 1.50 L = 0075 moles of AgNo3