Question

Use the periodic table in the tools bar to answer these questions. How many moles of AgNO3 are present in 1.50 L of a 0.050 M solution?

Answer 1

M= moles de soluto / litros de solucion 
moles de soluto = M. litros de solucion 

Moles de soluto = 0.050 M x 1.50 L = 0.075 moles de AgNo3

Answer 2

m = Solute moles/liters solution moles of solute =

m. Liters of solution moles of solute = 0050 m x 1.50 L = 0075 moles of AgNo3