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4 years ago

Which material does not melt at any temperature?

Chemistry

1 answer:

lord [1]4 years ago

6 0

Answer: Option (c) is the correct answer.

Explanation:

Wood is a mixture of different substances. Primarily it consists of cellulose, lignin, water etc.

When we heat wood then all these substance oxidize into the atmosphere even before they could melt.

Whereas iron, sodium chloride and ethanol all are the substances which can melt at any temperature.

Thus, we can conclude that out of the given options, wood, a mixture of different substances is a material that does not melt at any temperature.

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If 8.0 g of sulfur dioxide came in contact with a cloud containing 2.2 g of oxygen, indicate the

Inga [223]

Answer:

Limiting reactant= SO₂, Theoretical yield = 9.6g SO₃

Explanation:

The first step is is to find the limiting reactant; you do this using stoichiometry.

The reactant that produces the smallest amount of sulfur trioxide SO₃, is the limiting reactant.

In this problem, SO₂ is the limiting reactant.

Now to find the theoretical yield we will use the smallest value of SO₃.

I have uploaded a picture to better illustrate the problem and hope it helps.

5 0

3 years ago

Students are designing an experiment to test the law of conservation of mass using the following materials: 10 g baking soda, 30

Ivan

it would be 50ml hope th

8 0

2 years ago

How much heat do you need to raise the temperature of 150g of ice from -30°C to -15°C?

adoni [48]

I believe the answer is c

7 0

3 years ago

What is the volume of 90.0 grams of ether if the density of ether is 0.70 g/mL?

Mekhanik [1.2K]

Answer:

b) 1.3 E2 mL

Explanation:

density = mass / volume

∴ m = 90.0 g

∴ density = 0.70 g/mL

⇒ V = m / d

⇒ V = 90.0g / 0.70 g/mL

⇒ V = 128.571 mL

⇒ V = 1.285 E2 mL ≅ 1,3 E2 mL

3 0

3 years ago

Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing indi

AlexFokin [52]

Explanation:

The given cell reaction is as follows.

$In(s)| In^{3+}(aq) || Cd^{2+}(aq) | Cd(s)$

Hence, reactions taking place at the cathode and anode are as follows.

At anode ; Oxidation-half reaction : $In(s) \rightarrow In^{3+}(aq) + 3e^{-}$ ...... (1)

At cathode; Reduction-half reaction : $Cd^{2+}(aq) + 2e^{-} \rightarrow Cd(s)$ ....... (2)

Hence, balance the half reactions by multiplying equation (1) by 2 and equation (2) by 3.

Therefore, net cell reaction is as follows.

$2In(s) \rightarrow 2In^{3+}(aq) + 6e^{-}$

$3Cd^{2+}(aq) + 6e^{-} \rightarrow 3Cd(s)$

Net reaction: $2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

Thus, we can conclude that the overall cell reaction is as follows.

$2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

4 0

3 years ago