The beat frequency is the concept required to develop this process. The phenomenon is generated when you have two waves but their frequencies do not differ greatly. So the beat frequency will be the difference between those two waves. For this case we have the difference and one of the waves, therefore,
Our values are given as,
Using the formula of the frequency I will have,
Replacing we have,
The possible values are two: 1045Hz and 1055Hz
Answer:
Nuclear power plants are fueled by uranium, which emits radioactive substances. Most of these substances are trapped in uranium fuel pellets or in sealed metal fuel rods. However, small amounts of these radioactive substances (mostly gases) become mixed with the water that is used to cool the reactor.
Answer: D) dedicate as many hours as needed to the work.
Explanation:
edge 2020
Answer:
The distance between the slits is 3.55 μm
Explanation:
Given that,
Order number = 3
Wave length = 610 nm
Angle = 31°
We need to calculate the distance between the slits
Using formula of distance of slit
Where, n = order number
= wavelength
Put the value into the formula
Hence, The distance between the slits is 3.55 μm.
Answer:
t = 1,28 s
Explanation: This problem is a projectile motion problem.
V₀ₓ = V₀ * cosθ
Vₓ = constant all the way
Vₓ = V₀ₓ
tanθ = Vyi/Vxi that means in any point of the trajectory
tanθ = 6 / 60 ( just before touching the ground )
tanθ = 0,1 then arctan 0,1 ≈ 6⁰
sin 6⁰ = 0,1045
cos 6⁰ = 0,9945
V₀ₓ = V₀ * cosθ ⇒ V₀ = V₀ₓ / cosθ ⇒ V₀ = 60 / 0,9945
V₀ = 60,33 m/s
V₀y = V₀ * sin θ ⇒ V₀y = 60,33 * 0,1045 ⇒ V₀y = 6,30 m/s
Vy = V₀y - g * t
At maximum y Vy = 0 ( the middle of the trajectory)
g*tm = V₀y ⇒ tm= V₀y / g
tm = 6,30 / 9,8
tm = 0,64 s ( time to reach maximum y )
Then the time of fligh is twice 0,64 s
t = 0,64 * 2
t = 1,28 s
