Option D
When you squeeze an air-filled balloon, what happens inside: There are more collisions of air molecules against the wall of the balloon.
<u>Explanation:</u>
If you compress off the balloon, one seemingly sense the air forcing up on the wall of the balloon with indeed more imposing power. This rise in force is due to a drop in quantity. By squeezing the balloon, you lessen the area the gas bits can hold.
As the particles are driven a little closer collectively, they oppose more, so the force from the moving gas bits rises. Boyle’s Law pronounces that the quantity of a determined quantity of gas limits as its load rises. If the quantity rises, its load reduces.
Alpha helix and beta sheets are the secondary structure of protein
The water levels would lower, because as the moon gets farther away, it's gravitational pull decreases. Hope this helps! :)
Answer:
Explanation:
El hielo encierra la primavera antes de espolvorear la sal.
Cuando se rocía sal sobre el hielo, disminuye el punto de fusión del hielo 32 ° F a un poco por debajo de 32 °, por lo tanto, se acumula.
A medida que el hielo se vuelve a congelar, encierra la primavera
Answer:
Molar mass→ 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol
Explanation:
Let's apply the formula for freezing point depression:
ΔT = Kf . m
ΔT = 74.2°C - 73.4°C → 0.8°C
Difference between the freezing T° of pure solvent and freezing T° of solution
Kf = Cryoscopic constant → 5.5°C/m
So, if we replace in the formula
ΔT = Kf . m → ΔT / Kf = m
0.8°C / 5.5 m/°C = m → 0.0516 mol/kg
These are the moles in 1 kg of solvent so let's find out the moles in our mass of solvent which is 0.125 kg
0.0516 mol/kg . 0.125 kg = 6.45×10⁻³ moles. Now we can determine the molar mass:
Molar mass (mol/kg) → 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol
