Answer:
C is correct I think.
Step-by-step explanation:
Tell me if I am right.
Have a nice day!
Answer:
prolly 12
Step-by-step explanation:
it is probably 12 thank you
Answer:
V=πr2h
/3
Step-by-step explanation:
Answer:
≈0.487
Step-by-step explanation:
I think this is your full question right?
Jose surveyed the length of TV commercials (in seconds). Find, to 3 decimal places, the experimental probability that a randomly chosen TV commercial will last:
Length Frequency
0-19 17
20-39 38
40-59 19 20 to 39 seconds.
60+ 20 to 4
Here is my anwer:
experimental probability = relative frequency =
Total frequencies = 17 + 38 +18 + 4 = 78
P(20 to 39s) = 38/78 ≈0.487
<span>The answer is 0.00001267 m = 1.267 * 10^(-5) m. In scientific notation, the number is written as two factors - a number m from 0-10 and 10 raised to the n power: m x 10^n. 0.00001267 m = 1.267 x 0.00001 m. 0.00001 m = (0.1)^5 = 10^(-5). So: 0.00001267 m = 1.267 x 0.00001 m = 1.267 x (0.1)^5 m = 1.267 x 10^(-5) m.</span>