C= the price of a cheeseburger and l = the price of a lemonade:
Divide the second equation by -2 to begin the process of solving by elimination:
Now that we have c, 4, we can plug it in to one of the equations to find l:
So, each cheeseburger is $4 and each lemonade is $1. The final answer is:
1 cheeseburger and 2 cups of lemonade would cost $6.
Answer:
Step-by-step explanation:
the formula used for any interest other then continuously is
A=P(1+r/n)^nt
so... r=rate in decimal form ONLY n=how often interest is paid t=time passed
A=3000(1+.08/1)^(1)(5) = annually
A=3000(1+.08/2)^(2)(5)
A=3000(1+.08/4)^(4)(5)
use you calculator to get the answer
it is good practice to use your calculator now because soon you will be using it for population questions and those need to be entered very carefully.
Answer:
18
Step-by-step explanation:
32.25-9.85
22.5/1.25
18
Answer:
Step-by-step explanation:
The discriminant is used to determine the number and nature of the zeros of a quadratic. If the discriminant is positive and a perfect square, there are 2 rational zeros; if the discriminant is positive and not a perfect square, there are 2 rational complex zeros; if the discriminant is 0, there is 1 rational root; if the discriminant is negative, there are no real roots.
The roots/solutions/zeros of a quadratic are where the graph goes through the x axis. Those are the real zeros, even if they don't fall exactly on a number like 1 or 2 or 3; they can fall on 1.32, 4.35, etc. They are still real. If the graph doesn't go through the x-axis at all, the zeros are imaginary because the discriminant was negative and you can't take the square root of a negative number. As you can see on our graph, the parabola never goes through the x-axis. Therefore, the zeros are imaginary because the discriminant was negative. Choice C. Get familiar with your discriminants and the nature of quadratic solutions. Your life will be much easier!
Answer:
The equation of the line passing through the points (-2,0) and (0,-4)
The equation of the line passing through the points (0,-2) and (4,0)
Option B
x minus 2 y = 4 and 2 x + y = negative 4
