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weqwewe [10]
2 years ago
6

The revival of jansenism, which centered on miracles that allegedly happened at the grave of a jansenist priest, is evidence of

what development within french catholicism?
Chemistry
1 answer:
lapo4ka [179]2 years ago
3 0

The evidence of the revival of Jansenism is the desire of ordinary people to connect themselves to what they saw as the direct work of God.

<h3>What is Jansenism?</h3>

Jansenism is a theological movement that is done with the mixing of Catholicism. It was active in France's kingdom.

Primarily throughout the seventeenth and eighteenth centuries, Jansenism flourished inside Roman Catholicism before being denounced as heresy in 1653 by Pope Innocent X.

Thus, the yearning of common people to participate in what they perceived as God's direct action is proof of the rebirth of Jansenism.

To learn more about Jansenism, refer to the link:

brainly.com/question/14563019

#SPJ4

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Small quantities of hydrogen gas can be prepared in the lab by addition of hydrochloric acid to zinc. The gas is typically colle
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Answer:

0.214 L

Explanation:

Step 1: Write the balanced equation

This is a single displacement reaction.

Zn(s) + 2 HCl(aq) ⇒ ZnCl₂(aq) + H₂(g)

Step 2: Calculate the moles corresponding to 0.625 g of Zn

The molar mass of Zn is 65.38 g/mol.

0.625 g × 1 mol/65.38 g = 9.56 × 10⁻³ mol

Step 3: Calculate the moles of H₂ produced from 9.56 × 10⁻³ moles of Zn

The molar ratio of Zn to H₂ is 1:1. The moles of H₂ produced are 1/1 × 9.56 × 10⁻³ mol = 9.56 × 10⁻³ mol.

Step 4: Calculate the volume occupied by 9.56 × 10⁻³ moles of hydrogen

Assuming standard pressure and temperature, 1 mole of hydrogen occupies 22.4 L.

9.56 × 10⁻³ mol × 22.4 L/1 mol = 0.214 L

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Properties of solids depend on:​
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Answer:intra and intermolecular force of attraction

Explanation:

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A student sets up two reactions. Reaction 1 uses 0.290 mol/L of reactant, and Reaction 2 uses 0.470 mol/L of reactant. How many
34kurt

Reaction 2 will be 1.621 times faster than reaction 1

<u>Explanation:</u>

As the reaction 2 is taking 0.470 mol /L and reaction 1 is taking 0.290 mol /L, then the ratio of the rate of reaction will be

                   \text { Ratio }=\frac{\text { rate of reaction } 1}{\text { rate of reaction } 2}=\frac{0.470}{0.290}=1.6207

Asked reaction 2 how much faster than reaction 1, so rearrange the above equation, we get,            rate of reaction 2=\frac{\text { rate of reaction } 1}{\text { ratio }}=\left(\frac{1}{1.6207}\right) rate of reaction 1

Thus, 1.621 times reaction 2 is faster than reaction 1 as per the given question. As the reaction 2 is using more amount of reactants compared to reaction 1, the reaction 2 will be 1.6207 times faster than reaction 1.

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