Answer:
Explanation:
Truck velocity=50 km/hr
police car velocity =45 km/hr
Let they start at t=0 s
After one hour
truck displacement
In vector Form
For Police car displacement
in vector form


Answer:
Before the plank will tip cat will walk 1.652 m
Explanation:
Mass of the cat along with plank 
Center of mass of the plank 
Mass of cat 
We have to find how far right of sawhorse B.
Plank will tip when weight of the cat about B is greater than the torque by the weight of the plank.
Balancing the the torque



<span> Light energy is verified by many scientists to be made of particles called photons. The amount of energy in each photon is related to its wavelength using the Planck-Einstein equation. </span><span>Nuclear energy the binding energy of atomic nuclei which holds the subatomic particles within the nucleus.</span>
Answer:

Explanation:
From the question we are told that:
Frictional force 
Coefficient of kinetic friction 
Generally the equation for Normal for is mathematically given by

Therefore


Answer:
a) 4.9*10^-6
b) 5.71*10^-15
Explanation:
Given
current, I = 3.8*10^-10A
Diameter, D = 2.5mm
n = 8.49*10^28
The equation for current density and speed drift is
J = I/A = (ne) Vd
A = πD²/4
A = π*0.0025²/4
A = π*6.25*10^-6/4
A = 4.9*10^-6
Now,
J = I/A
J = 3.8*10^-10/4.9*10^-6
J = 7.76*10^-5
Electron drift speed is
J = (ne) Vd
Vd = J/(ne)
Vd = 7.76*10^-5/(8.49*10^28)*(1.60*10^-19)
Vd = 7.76*10^-5/1.3584*10^10
Vd = 5.71*10^-15
Therefore, the current density and speed drift are 4.9*10^-6
And 5.71*10^-15 respectively