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alexandr1967 [171]
3 years ago
6

What is the solution to the equation 3/ x+4+3/2x+8 = 0?

Mathematics
1 answer:
mixas84 [53]3 years ago
5 0

Answer:

X= -4

Step-by-step explanation:

^ you have to isolate the radical than raise each side to the power of its index which gets you

x= -4

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you are adding two rational numbers with different signs. how can u tell if the sum will be positive,negative,zero
Lorico [155]
You can tell if it is going to be negative if there is a number with a greater value. for example -14 minus 7. that would be -7 
You can tell if it is positive if one number has a bigger value. for example 12-(-6)=6
And if it is zero it would be something like this
-7+7 sorry that's hard to explain in words hoped this helped you
5 0
3 years ago
Please help me it’s due right now?!?! <br> Find the missing side of each triangle.
Sever21 [200]

Answer:

x = 2√5

Step-by-step explanation:

Using the Pythagorean Theorem:

a² + b² = c²

You can identify that x is the hypotenuse, as it is opposite to the right angle.

So:

3² + √11² = x²

9 + [(√11) (√11)] = x²

9 + 11 = x²

20 = x²

√20 = √x²

√4√5 = x

2√5 = x

x = 2√5

7 0
3 years ago
23 tens is the same as
choli [55]
230 ones!! Hopefully i helped Have a great day....and if my answer was best plzz give brainliest plzz!

3 0
3 years ago
Read 2 more answers
Find the distance between the two points in simplest radical form.<br> (-9,8) and (-3, -1)
dmitriy555 [2]

Answer:

The distance between (-9, 8) and (-3, -1) will be:

\:d=3\sqrt{13} units

Step-by-step explanation:

Given the points

  • (-9, 8)
  • (-3, -1)

Finding the distance between (-9, 8) and (-3, -1)

d\:=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

   =\sqrt{\left(-3-\left(-9\right)\right)^2+\left(-1-8\right)^2}

   =\sqrt{\left(-3+9\right)^2+\left(-1-8\right)^2}

   =\sqrt{36+81}

   =\sqrt{117}

   =3\sqrt{13} units

Therefore, the distance between (-9, 8) and (-3, -1) will be:

\:d=3\sqrt{13} units

7 0
3 years ago
The base of a cube is parallel to the horizon. If the cube is cut by a plane to form a cross section, under what circumstance wo
Keith_Richards [23]
This question has this set of answer choices:

a) when the plane cuts three faces of the cube, separating one corner from the others

b) when the plane passes through a pair of vertices that do not share a common face

c) when the plane is perpendicular to the base and intersects two adjacent vertical faces

d) when the plane makes an acute angle to the base and intersects three vertical faces

e) not enough information to answer the question

The right answer is the first choice: a) when the plane cuts three faces of the cube, separating one corner from the others

You can see a picture of this case in the figure attached: as you can see the cross section (in pink) is a triangle.

8 0
3 years ago
Read 2 more answers
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