Answer:
Explanation:
For the reaction
C2H5OH (l) + 3 O2(g) = 2CO2(g) + 3 H2O
We can calculate the standard molar enthalpy of combustion using the standard enthalpies of formation of the species involved in the reaction according to Hess law:
ΔHºc = 2ΔHºf CO2 (g) + 3ΔHºfH2O(l) - ( ΔHºf C2H5OH (l) - 3ΔHºfO2 (g) )
( we were not give the water state but we know we are at standard conditions so it is in its liquid state )
The ΔHºfs can be found in appropiate reference or texts.
ΔHºc = 2ΔHºf CO2 (g)+ 3ΔHºfH2O(l) - ( ΔHºf C2H5OH (l) -+3ΔHºfO2 (g) )
= [ 2 ( -393.52 ) + 3 ( -285.83 ) ] - [( -276.2 + 0 ) ] kJ
ΔHºc = -1368.33 kJ
Answer:
Moles of 
= 6 moles
Explanation:
The reaction of 
and 
to make is:
⇒
The above reaction shows that 2 moles of Sc can react with 3 moles of to form 
Mole Ratio= 2:3
For 10 moles of Sc we need:
Moles of = 
Moles of = 
Moles of =15 moles
So 15 moles of are required to react with 10 moles of but we have 9 moles of , it means is limiting reactant.
Moles of ScCl_3= 6 moles
Answer:
2.5 L
Explanation:
The stoichiometric ratio of N2 to N2O4 is 1:1
Answer:
1. NaOH + H₂O → Na⁺ + OH⁻ + H₂O + heat
2. NaOH + HCl → NaCl + H₂O
Explanation:
1. The dissolving of NaOH in water is an exothermic reaction resulting a heat. It also causes the dissociation of NaOH to its ions (Na⁺ and OH⁻).
So, the balanced equation will be NaOH + H₂O → Na⁺ + OH⁻ + H₂O + heat.
2. The reaction between acid and base resulting salt and water. It is considered as a neutralization reaction.
The reaction between HCl and NaOH will give sodium chloride and water and the balanced equation will be NaOH + HCl → NaCl + H₂O.
