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ExtremeBDS [4]
3 years ago
7

13.2.2 7+6 - 9(-2)+(-3)​

Physics
1 answer:
aniked [119]3 years ago
4 0

Answer:

34.27 is the answer

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If the density of wood is 0.5g/cm3 what is the mass of 1cm3​
Licemer1 [7]

Answer:

O. 5 g

Explanation:

It literally says for every cm3 its 0.5 g

5 0
3 years ago
Does wavelength affect the energy of a wave?
Galina-37 [17]

Answer:

Not quite

Explanation:

The frequency of a wave is inversely proportional to its wavelength. That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength

What determines the strength of a wave?

Wave height is affected by wind speed, wind duration (or how long the wind blows), and fetch, which is the distance over water that the wind blows in a single direction. If wind speed is slow, only small waves result, regardless of wind duration or fetch.

So,

As Wavelength increases, The energy of the wave spreads and it decreases

4 0
2 years ago
Why a pond of water appears shallower than it actually is?​
GalinKa [24]
The refraction of light at the surface of water makes ponds look shallower then they really are
3 0
3 years ago
A car with a velocity of 30 mph
Leokris [45]

Answer:

First calculate the deceleration making use of the formulation: V(very last speed= U(initial speed) -a(acceleration) t(ime) so 10=20- 4a. unfavourable a as decelerating. making a the acceleration the challenge by using rearranging the elements 4a= 20-10 = 10 so a=10/4 making use of Newton's 2d regulation P(stress) = M (mass) x A (acceleration). so P = 800 x 10/4 = 8000 /4 = 2000 newtons

Explanation:

4 0
3 years ago
The tub of a washing machine goes into its spin cycle, starting from rest and gaining angular speed steadily for 6.00 s, at whic
MatroZZZ [7]

Answer:

N = 42 rev

Explanation:

As we know that initial angular speed of the tub was zero and then it increases uniformly to 4 rev/s in t = 6.00 s

so we will have

\theta_1 = \frac{\omega_f + \omega_i}{2} t

\theta_1 = \frac{2\pi f_2 + 2\pi f_1}{2}(t)

\theta_1 = \frac{2\pi \times 4 + 0}{2}(6)

\theta_1 = 75.4 rad

Now when the tub will comes to rest uniformly after opening the lid in time interval of t = 15 s

then we have

\theta_2 = \frac{\omega_f + \omega_i}{2} t

\theta_2 = \frac{2\pi f_2 + 2\pi f_1}{2}(t)

\theta_2 = \frac{2\pi \times 4 + 0}{2}(15)

\theta_2 = 188.5 rad

Now total angular displacement of the tub is given as

\theta = \theta_1 + \theta_2

\theta = 75.4 + 188.5

\theta = 263.9 rad

so number of revolutions is given as

\N = \frac{\theta}{2\pi}

N = 42 rev

3 0
3 years ago
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