Answer:
Acids are sour in taste. Acids react with carbonates and hydrogen carbonates to form a salt, water, and carbon dioxide gas. Extremely active metals such as Potassium (K), Calcium (Ca), Sodium (Na), etc tend to explode when combined with acids. Weak Acids like Carbonic Acid doesn't act with any metal at all.
I copied and pasted
but I hope the info helps
Answer:
its c I think C)
The reason for this is due to the phenomenon called "Charging by Induction". What that means is that when something with a charge, for example a negative charge, is brought near an uncharged one, it induces the opposite charge onto it (positive in this case) and therefore since opposites attract, it attracts it.
The reason for this is that since, just like a positive magnet rejects and pushed away like charges, the electrons hold a negative charge, they push away any electrons that may be in the neutrally charged item causing only protons to be left, thus creating an oppositely charged object. Or vice versa.
So whatever charge the object has, it induces the opposite charge into the uncharged object, causing the charges to move only in the uncharged one.
Explanation:
<u>Answer:</u> The outermost valence electron enters the p orbital.
<u>Explanation:</u>
Valence electrons are defined as the electrons which are present in outer most orbital of an atom.
Sulfur is the 16th element of the periodic table having 16 electrons.
Electronic configuration of sulfur atom is 
The number of valence electrons are 2 + 4 = 6
These 6 electrons enter s-orbital and p-orbital but the outermost valence electron will enter the p-orbital.
Hence, the outermost valence electron enters p orbital.
<u>Answer:</u> The hydroxide ion concentration and pOH of the solution is
and 2.88 respectively
<u>Explanation:</u>
We are given:
Concentration of barium hydroxide = 0.00066 M
The chemical equation for the dissociation of barium hydroxide follows:

1 mole of barium hydroxide produces 1 mole of barium ions and 2 moles of hydroxide ions
pOH is defined as the negative logarithm of hydroxide ion concentration present in the solution
To calculate pOH of the solution, we use the equation:
![pOH=-\log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5BOH%5E-%5D)
We are given:
![[OH^-]=(2\times 0.00066)=1.32\times 10^{-3}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D%282%5Ctimes%200.00066%29%3D1.32%5Ctimes%2010%5E%7B-3%7DM)
Putting values in above equation, we get:

Hence, the hydroxide ion concentration and pOH of the solution is
and 2.88 respectively
The focal length, like you said it's the distance between the FOCAL point and the mirror.
Hope this helps.... :)