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USPshnik [31]
3 years ago
9

Describe and explain how petrol is separated from the mixture of hydrocarbons in crude oil.

Chemistry
1 answer:
Anna71 [15]3 years ago
8 0
The process is called fractional distillation.  It works by heating up the crude oil inside a chamber to a boil (vaporizing it). Due to the fact that each component of crude oil has a different boiling point, each component of the crude oil will condense at a different height inside the chamber since the chamber gets colder the further up you go away from the heat source. Since each component condenses at different heights in the chamber, there are places to collect condensing liquid at different heights in the chamber (The heights correspond to the boiling point of each component).  These collection areas will collect only the component of crude oil that condenses at that temperature.  The condensing point is basically the boiling point which means the lower in the chamber that component condenses at, the higher the boiling point for that component is and therefore the heavier that component is (the heavier components get collected near the bottom of the chamber while the lighter components get collected near the top of the chamber).

I hope this helps.  Let me know if anything is unclear.
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What is a physical change
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6 0
4 years ago
Read 2 more answers
A 8.00g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of
Ne4ueva [31]

Answer:

C3H6.

Explanation:

Data obtained from the question:

Mass of the compound = 8g

Mass of CO2 = 24.01g

Mass of H2O = 13.10g

Next, we shall determine the mass of C, H and O present in the compound. This is illustrated below:

Molar Mass of CO2 = 12 + (2x16) = 44g/mol

Molar Mass of H2O = (2x1) + 16 = 18g/mol

Mass of C in compound = Mass of C/Molar Mass of CO2 x 24.01

=> 12/44 x 24.01 = 6.5g

Mass of H in the compound = Mass of H/Molar Mass of H2O x 13.1

=> 2x1/18 x 13.1 = 1.5g

Mass of O in the compound = Mass of compound – (mass of C + Mass of H)

=> 8 – (6.5 + 1.5) = 0

Next, we shall determine the empirical formula of the compound. This is illustrated below:

C = 6.5g

H = 1.

Divide by their molar mass

C = 6.5/12 = 0.54

H = 1.4/1 = 1.

Divide by the smallest

C = 0.54/0.54 = 1

H = 1/0.54 = 2

Therefore, the empirical formula is CH2

Finally, we shall determine the molecular formula as follow:

The molecular formula of a compound is a multiple of the empirical formula.

Molecular formula = [CH2]n

[CH2]n = 44

[12 + (2x1)]n = 44

14n = 44

Divide both side by 14

n = 44/14

n = 3

Molecular formula = [CH2]n = [CH2]3 = C3H6

Therefore, the molecular formula of the compound is C3H6

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