Myra kicked the stone with an initial speed of 8.15 m/s at an angle of 30° above the horizontal.

Newton's second law is a major part of mechanics. However, it does have its limitations. Under what condition does the second la

Pavel [41]

Answer:

Newton's second law only applies in an inertial frame of reference.

Explanation:

An inertial frame of reference is not accelerating. An observer on the ground is in an inertial frame of reference. He can use Newtons laws to describe a rocket launch. The person inside the rocket is not in an inertial frame of reference when the rocket is launched. Newtons laws can not be used by the person inside the rocket.

7 0

3 years ago

Why is it advised not to hold the thermometer by its bulb while reading it?

Fiesta28 [93]

Because your body heat might change the temperature

7 0

3 years ago

Read 2 more answers

Classify the animal hydra and plant mustard with two characters of each

inna [77]

Answer:

Mustard seeds, both white and brown, are nearly globular in shape, finely pitted, odourless when whole, and pungent-tasting

Image result for character of hydra

Introduction: Hydra are inconspicuous freshwater relatives of corals, sea anemones and jellyfish. All are members of the phylum Cnidaria, characterized by radially symmetrical bodies, presence of stinging tentacles and a simple gut with only one opening (gastrovascular cavity)

Explanation:

Hydra are a genus of small, fresh-water organisms that are classified under the phylum Cnidaria.the classification of mustard is

Dicotyledons

if my answer helps you than mark me as brainliest

4 0

3 years ago

Serving at a speed of 164 km/h, a tennis player hits the ball at a height of 2.23 m and an angle θ below the horizontal. The ser

sweet-ann [11.9K]

Answer:

The angle θ is 6.1° below the horizontal.

Explanation:

Please, see the figure for a description of the situation.

The vector "r" gives the position of the ball and can be expressed as the sum of the vectors rx + ry (see figure).

We know the magnitude of these vectors:

magnitude rx = 11.6 m

magnitude ry = 2.23 m - 0.99 m = 1.24 m

Then:

rx = (11. 6 m, 0)

ry = (0, -1.24 m)

r = (11.6 m + 0 m, 0 m - 1.24 m) = (11.6 m, -1.24 m)

Using trigonometry of right triangles:

magnitude rx = r * cos θ = 11. 6 m

magnitude ry = r * sin θ = 2.23 m - 0.99 = 1.24 m

where r is the magnitude of the vector r

magnitude of vector r:

$r = \sqrt{(11.6m)^{2} + (1.24m)^{2}} = 11.667m$

Then:

cos θ = 11.6 m / 11.667 m

θ = 6.1°

Using ry, we should obtain the same value of θ:

sin θ = 1.24 m/ 11.667 m

θ = 6.1°

( the exact value is obtained if we do not round the module of r)

7 0

3 years ago

An object of mass m attached to a spring of force constant k oscillates with simple harmonic motion. The maximum displacement fr

Lady_Fox [76]

An object of mass m attached to a spring of force constant k oscillates with simple harmonic motion. The system's potential energy when kinetic energy of (3/4) E is (1/8) k A².

<h3>What is mechanical energy?</h3>

Mechanical energy is the sum of potential energy and kinetic energy.

Total mechanical energy = P.E max = K.E max

Total mechanical energy = K.E +P.E

Given is the kinetic energy is (3/4)E.

E= (3/4)E + P.E

P.E = (1/4) E

Maximum potential energy =E = (1/2) k A²

Here. A is the maximum displacement and k is the spring constant.

The potential energy at kinetic energy of (3/4) E is

P.E = (1/4)E = (1/8) k A²

Therefore, the system's potential energy when kinetic energy of (3/4) E is (1/8) k A².

Learn more about mechanical energy.

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6 0

2 years ago