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3 years ago

Which element would be expected to have a similar physical and chemical properties as oxygen, and why?

Chemistry

1 answer:

soldi70 [24.7K]3 years ago

5 0

Oxygen and Sulfur are in the same group.

Sulfur is the next element in the group, and it reacts with hydrogen gas (H2) in a manner similar to oxygen.

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A gas phase mixture of H2 and N2 has a total pressure of 784 torr with an H2 partial pressure of 124 torr. What mass of N2 gas i

olchik [2.2K]

The mass of N₂ in the mixture having a total pressure of 784 torr with an H₂ partial pressure of 124 torr is 1.988 g

We'll begin by calculating the partial pressure of N₂. This can be obtained as follow:

Total pressure = 784 torr

Partial pressure of H₂ = 124 torr

<h3>Partial pressure of N₂ =?</h3>

Total pressure = Partial pressure of H₂ + Partial pressure of N₂

784 = 124 + Partial pressure of N₂

Collect like terms

Partial pressure of N₂ = 784 – 124

<h3>Partial pressure of N₂ = 660 Torr</h3>

Next, we shall determine the number of mole of N₂ in the mixture.

Pressure of N₂ (P) = 660 Torr

Volume (V) = 2 L

Temperature (T) = 298 K

Gas constant (R) = 62.364 L.Torr/Kmol

<h3>Number of mole of N₂ (n) =? </h3>

PV = nRT

660 × 2 = n × 62.364 × 298

1320 = n × 18584.472

Divide both side by 18584.472

n = 1320 / 18584.472

Finally, we shall determine the mass of N₂ in the mixture.

Mole of N₂ = 0.071 mole

Molar mass of N₂ = 2 × 14 = 28 g/mol

Mass = mole × molar mass

Mass of N₂ = 0.071 × 28

Therefore, the mass of N₂ in the mixture having a total pressure of 784 torr with an H₂ partial pressure of 124 torr is 1.988 g

Learn more: brainly.com/question/20853110

4 0

2 years ago

For many purposes we can treat propane (CH) as an ideal gas at temperatures above its boiling point of - 42°C. Suppose the tempe

fredd [130]

Answer: The final pressure is 0.81 kPa

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.58 kPa

$P_2$ = final pressure of gas = ?

$V_1$ = initial volume of gas = v

$V_2$ = final volume of gas = $v-\frac{40}{100}\times v=0.6v$

$T_1$ = initial temperature of gas = $25^0C=(25+273)K=298K$

$T_2$ = final temperature of gas = $-22^0C=(-22+273)K=251K$

Now put all the given values in the above equation, we get:

$\frac{0.58\times v}{298}=\frac{P_2\times 0.6v}{251}$

$P_2=0.81kPa$

The final pressure is 0.81 kPa

3 0

3 years ago

What is the daily cost of incandescent lamp

Grace [21]

I think the answer is $0.03

6 0

3 years ago

A sailboat is pushed by a steady wind with a force of 4000 N. Its acceleration is 2

AveGali [126]

Answer:

Explanation:

The mass of the sailboat can be found by using the formula

$m = \frac{f}{a} \\$

f is the force

a is the acceleration

From the question we have

$m = \frac{4000}{2} \\$

We have the final answer as

Hope this helps you

6 0

3 years ago

Which subatomic particle do you think is most important to an atom’s identity?

Sonja [21]

The subatomic particle that identifies the atom is the number of protons. This is what distinguishes an element that is is flammmable, hydrogen to one that is essential component in water, oxygen.

5 0

4 years ago