Enumerating the data points from the chart over ten years:
{100, 105, 95, 102, 93, 105, 98, 99, 101, 100}
Their initial, final, and the median values are all 100. The mean value is 99.8, and the standard deviation slightly less than 3.9. All of these statistics indicate stability of the population over the observed span of ten years. There is neither a significant growth, nor a decline. Assuming stability is what corresponds to a species doing well in a habitat, a conclusion can be made that the species is doing well!
Provided the conditions of the artificial habitat won't change significantly in the next five years, the population will continue to remain close to an average of 100, with minor deviations of +/- 4 likely year by year.
(1.00 atm) (0.1156 L) = (n) (0.08206 L atm / mol K) (273 K) I hoped that helped
Scientist judge each others work based mostly on how creative it is.
Answer:
the final velocity of the wagon is 6 m/s.
Explanation:
Given;
initial velocity of the wagon, u = 4 m/s
mass of the wagon, m = 35 kg
energy applied to the wagon, E = 350 J
The final velocity of the wagon is calculated as;
E = ¹/₂m(v² - u²)

Therefore, the final velocity of the wagon is 6 m/s.
Answer:
The highest pressure is located at points x & y.
Explanation:
The pressure will be greater at the X & y points, because they are at a deeper distance than the Z point. We must remember that the pressure is a function of the depth of the fluid, and is expressed by the following equation.
![P = densi*g*h\\where\\densi = density [kg/m^3]\\g = gravity [m/s^2]\\h = elevation [m]](https://tex.z-dn.net/?f=P%20%3D%20densi%2Ag%2Ah%5C%5Cwhere%5C%5Cdensi%20%3D%20density%20%5Bkg%2Fm%5E3%5D%5C%5Cg%20%3D%20gravity%20%5Bm%2Fs%5E2%5D%5C%5Ch%20%3D%20elevation%20%5Bm%5D)
The pressure is always measured with respect to the liquid level towards the depth of the fluid, so at greater depth greater pressure