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kati45 [8]
3 years ago
12

A 50 N force causes a spring to compress 0.09 m. What is the spring constant? What is the potential energy of the spring?​

Physics
1 answer:
Svetlanka [38]3 years ago
5 0
<h3><u><em>Initial considerations</em></u></h3>
  • <em>Applied force = 50N</em>
  • <em>Distance to equilibrium position = 0.09m</em>
  • <em>Spring constant = ?</em>

<em />

<h3><u><em>Resolution</em></u></h3>

<em>using hooke's relation </em>

<em>F = K . d</em>

<em>50N = k . 0.09m</em>

<em>k = 50N / 0.09m</em>

<em>k = 5555.56 N/m</em>

<em />

<em>Calculating the potential energy of the spring</em>

<em>Ep = 1/2 k . x²</em>

<em>Ep = 1/2 (5555.56 N/m) (0.09m)²</em>

<em>Ep = 22.5 Joules</em>

<em />

<h3><u><em>Answer</em></u></h3>

<em>the spring constant? =</em>

<em>k =  5555.56 N/m</em>

<em>potential energy of the spring?​</em>

<em>Ep = 22.5 Joules</em>

<em />

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