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kati45 [8]
3 years ago
12

A 50 N force causes a spring to compress 0.09 m. What is the spring constant? What is the potential energy of the spring?​

Physics
1 answer:
Svetlanka [38]3 years ago
5 0
<h3><u><em>Initial considerations</em></u></h3>
  • <em>Applied force = 50N</em>
  • <em>Distance to equilibrium position = 0.09m</em>
  • <em>Spring constant = ?</em>

<em />

<h3><u><em>Resolution</em></u></h3>

<em>using hooke's relation </em>

<em>F = K . d</em>

<em>50N = k . 0.09m</em>

<em>k = 50N / 0.09m</em>

<em>k = 5555.56 N/m</em>

<em />

<em>Calculating the potential energy of the spring</em>

<em>Ep = 1/2 k . x²</em>

<em>Ep = 1/2 (5555.56 N/m) (0.09m)²</em>

<em>Ep = 22.5 Joules</em>

<em />

<h3><u><em>Answer</em></u></h3>

<em>the spring constant? =</em>

<em>k =  5555.56 N/m</em>

<em>potential energy of the spring?​</em>

<em>Ep = 22.5 Joules</em>

<em />

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a sprinter with a mass of 80kg accelerates uniformly from 0 m/s to 9 m/s in 3 s. a.)what is the runners acceleration? b.) what i
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Part A: 
Acceleration can be calculated by dividing the difference of the initial and final velocities by the given time. That is,
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Substituting,
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Part B: 
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<em>ANSWER: 240 N </em>

Part C: 
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         d = V₀t + 0.5at²

Substituting,
            d = (0 m/s)(3 s) + 0.5(3 m/s²)(3 s)²
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<em>ANSWER: d = 13.5 m</em>

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Answer:

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Explanation:

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         Em_{f} = U = mg h

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        Em₀ =  Em_{f}

        ½ m v² = m g h

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Now let's work with the tire that is a cylinder with the axis of rotation in its center of mass

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