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bezimeni [28]
3 years ago
6

GIVING BRAINLIEST PLEASE HELP!!

Physics
1 answer:
alisha [4.7K]3 years ago
6 0

Answer:

c is the right answer is it

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A student attaches a block to a vertical spring so that the block-spring system will oscillate if the block-spring system is rel
vodka [1.7K]

Answer:

Time period of the motion will remain the same while the amplitude of the motion will change

Explanation:

As we know that time period of oscillation of spring block system is given as

T= 2\pi\sqrt{\frac{M}{k}}

now we know that

M = mass of the object

k = spring constant

So here we know that the time period is independent of the gravity

while the maximum displacement of the spring from its mean position will depends on the gravity as

mg = kx

x = \frac{mg}{k}

so we can say that

Time period of the motion will remain the same while the amplitude of the motion will change

4 0
3 years ago
How many seconds will it take to travel 3,600 meters if your speed is 90 meters per second?
klio [65]
40

Because if you divide 3,600 by 90 it is equivalent to 40.

Hope this helps, have a blessed day :)
4 0
2 years ago
Which of these statements are true about hydroelectric power? A.It is the most widely used renewable energy source in the world.
Ede4ka [16]
D is the answer most true
6 0
2 years ago
Here are the questions you need to answer for this assignment. After reading the questions carefully, pick arbitrary numbers to
MrRissso [65]

Answer:

this dont even explain the question

Explanation:

5 0
2 years ago
Calculate the focal length of a lens needed by a woman whose near point is 50cm from her eyes, assuming the least distance of di
son4ous [18]

The focal length of a lens needed by a woman whose near point is 50cm from her eyes is 50cm.

To find the answer, we have to know about the focal length of correcting lens.

<h3>How to find the focal length of correcting lens?</h3>
  • If x is the distance of nearest point of the defective eye and D is the least distance of distinct vision, then, the expression for focal length of the correcting lens will be,

                           f=\frac{XD}{X-D}

  • It is given that, the woman whose near point is 50cm from her eyes, assuming the least distance of distinct vision for a normal eye is 25cm. Thus, the focal length will be,

                       f=\frac{50*25}{50-25} =50cm.

Thus, we can conclude that, the focal length of a lens needed by a woman whose near point is 50cm from her eyes is 50cm.

Learn more about the focal length here:

brainly.com/question/27915592

#SPJ9

4 0
1 year ago
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