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3 years ago

GIVING BRAINLIEST PLEASE HELP!!

Physics

1 answer:

alisha [4.7K]3 years ago

6 0

Answer:

c is the right answer is it

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A waterbed has a force of 1300N on the floor. It exerts 347 Pa of pressure. What is the area of the waterbed?

Sergio [31]

Answer:

Pressure = Force/Area

347 = 1300/Area

Area = 1300/347

area= 3.47m2

6 0

3 years ago

Read 2 more answers

When checking the charging system on a late-model vehicle: Technician A connects a scan tool to monitor the system voltage outpu

bearhunter [10]

Answer:

C) Both 1 and 2

Explanation:

The scan tool may include a bi-directional control that allows the technician to control the output of the alternator for testing purposes.

The Diagnostic Trouble Codes (DTCs), are used by automobile manufacturers to diagnose problems related to the vehicle.

The scan tool can also be used to monitor the output voltage of the vehicle to verify if the correct amount of voltage is supplied by the alternator.

Both Technicians A and B are correct because the steps they both take are necessary for the diagnosis of the vehicle.

5 0

3 years ago

What is the pressure exerted by a block of wood of mass 10 kg with an area of 0.1 m2

koban [17]

Answer:

0.01

Explanation:

8 0

3 years ago

An object on a spring whose constant is 30. N/m

MrRa [10]

The mass of the object is 0.0076 kg

Explanation:

The frequency of a mass-spring system (simple harmonic motion) is given by

$f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}$

where

f is the frequency

k is the spring constant

m is the mass

For the mass-spring system in this problem, we know:

k = 30 N/m is the spring constant

f = 10 Hz is the frequency

Solving the equation for m, we find the mass:

$m=\frac{k}{(2\pi f)^2}=\frac{30}{(2\pi (10))^2}=0.0076 kg$

#LearnwithBrainly

3 0

3 years ago

ball dropped from top of 50m high cliff stone thrown straight up from bottom with speed of 24. they collide. how far above base

Tresset [83]

Answer:

28.73 m from the base of the cliff collide happen

Explanation:

Equation for ball dropped from 50 cliff is reaches distance x in t seconds isi given by

$x=ut+\frac{1}{2} at^2\\\\x= 0 \times t+\frac{1}{2} gt^2 =\frac{1}{2} gt^2......(1)$

stone is thrown up from the bottom with speed u=24 m/s . it reaches distance y when stone collide with ball.(g is negative here)

$y=24t-\frac{1}{2} gt^2.............(2)$

we know that total distance traveled by ball and stone is 50 m

$x+y=50 m$

adding equation 1 and 2, we get time t

$x+y=\frac{1}{2} gt^2+24t-\frac{1}{2}gt^2\\50=24t\\t=2.083 s$

substitute this time in equation 2, we can get the required distance where they collide

$y=24t-\frac{1}{2} gt^2\\y=24\times 2.083-\frac{1}{2}\times 9.8\times 2.083^2\\y=28.73 m$

28.73 m from the base of the cliff collide happen

7 0

3 years ago