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marshall27 [118]
3 years ago
6

In 1929, American astronomer Edwin Hubble discovered that distant galaxies were moving away from us. He found that light from di

stant objects in the universe shifted in frequency towards the red color on the electromagnetic spectrum, which tells us that the objects are receding away from us.
What phenomenon is described in the passage above? Select the best answer from the choices below.

a
The Doppler Shift
b
Hubble's Law
c
The Big Bang
d
Dark matter
Physics
2 answers:
Novay_Z [31]3 years ago
7 0

Answer:

it is the Hubble law

Explanation:

Hubble's law, also known as the Hubble–Lemaître law, is the observation in physical cosmology that galaxies are moving away from the Earth at speeds proportional to their distance. In other words, the farther they are the faster they are moving away from Earth.

stepan [7]3 years ago
3 0

Answer:

The hubble law

is the observation in physical cosmology that galaxies are moving away from the Earth at speeds proportional to their distance. In other words, the farther they are the faster they are moving away from Earth.

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A cubical box measuring 1.29 m on each side contains a monatomic ideal gas at a pressure of 2.0 atm How much thermal energy do t
Marrrta [24]

Answer:

a) U = 652.545\,kJ, b) v \approx 659.568\,\frac{m}{s}

Explanation:

a) According to the First Law of Thermodinamics, the system is not reporting any work, mass or heat interactions. Besides, let consider that such box is rigid and, therefore, heat contained inside is the consequence of internal energy.

Q = U

The internal energy for a monoatomic ideal gas is:

U = \frac{3}{2} \cdot n \cdot R_{u} \cdot T

Let assume that cubical box contains just one kilomole of monoatomic gas. Then, the temperature is determined from the Equation of State for Ideal Gases:

T = \frac{P\cdot V}{n\cdot R_{u}}

T = \frac{(202.65\,kPa)\cdot(1.29\,m)^{3}}{(1\,kmole)\cdot(8.314\,\frac{kPa\cdot m^{3}}{kmole\cdot K} )}

T = 52.325\,K

The thermal energy contained by the gas is:

U = \frac{3}{2}\cdot (1\,kmole)\cdot (8.314\,\frac{kPa\cdot m^{3}}{kmole\cdot K})\cdot (52.325\,K)

U = 652.545\,kJ

b) The physical model for the cat is constructed from Work-Energy Theorem:

U = \frac{1}{2}\cdot m_{cat} \cdot v^{2}

The speed of the cat is obtained by isolating the respective variable and the replacement of every known variable by numerical values:

v = \sqrt{\frac{2 \cdot U}{m_{cat}}}

v = \sqrt{\frac{2\cdot (652.545 \times 10^{3}\,J)}{3\,kg} }

v \approx 659.568\,\frac{m}{s}

3 0
3 years ago
A peregrine falcon dives at a pigeon. The falcon starts with zero downward velocity and falls with the acceleration of gravity.
Reptile [31]

Answer:

t = 3.94 s

Explanation:

This can be modeled as a case of free fall motion. Because, the falcon is going down with acceleration, that is equal to acceleration due to gravity. To find the time taken by the falcon to intercept the pigeon, we will use second equation of motion for vertical direction:

h = v_{i}t + \frac{1}{2}gt^2

where,

h = height = 76 m

vi = initial speed of falcon = 0 m/s

t = time required = ?

g = acceleration due to gravity = 9.81 m/s²

Therefore,

76\ m = (0\ m/s)(t) + \frac{1}{2}(9.81\ m/s^2)t^2\\t^2 = \frac{(2)(76\ m)}{9.8\ m/s^2}\\\\t = \sqrt{ 15.49\ s^2}\\

<u>t = 3.94 s</u>

5 0
3 years ago
The standard unit for measuring volume is the _____. milliliter liter deciliter cubic centimeter
Natali [406]
Cubic centimeter is the answer
8 0
4 years ago
Read 2 more answers
A light-year is a unit of<br> a. time.<br> c. mass.<br> b. distance.<br> d. density.
lana [24]

Answer: The correct answer is Option b. Distance.

Explanation:

Scientists and astronomers use this unit to measure the distance in space. A light year is a unit of distance and not time because light travels very fast and it travels a lot of distance in one year.

Light year is basically defined as how far the beam of light travels in a year.

Therefore, this light year is a unit of distance. Hence, the correct option is option b.

1\text{ light year}=5.879\times 10^{12}miles

6 0
3 years ago
Read 2 more answers
What are the purposes of these items aboard the Voyager probes? • Low-energy particle detector: • Magnetometer boom: • High-gain
marta [7]

Explanation:

1. Low-energy particle detector: This particle detector measures the charged particles of the solar winds.

2. Magnetometer boom: This device measures magnetic fields produced by astronomical bodies.

3. High-gain antenna: A HGA has a narrow radio beam that is used to enhance the strength of signal. They simply amplify the weak signals.

4. Photopolarimeter: This is an instrument that is used to measure the strength and intensity and polarization of reflected light.

4 0
3 years ago
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