<h2>None of these forces contribute for these vibrations </h2>
Explanation:
The atoms or molecules of the solid substance vibrate at zero degree absolute even , due to kinetic energy of the constituent atoms or molecules .
According to Kelvin , the kinetic energy of these particles should become zero at absolute zero .
But it is found by actual calculations that the kinetic energy of constituent atoms or molecules does not become zero .
Thus all the above forces are not considered as the main cause of these vibration .
Period 1 has only two elements (hydrogen and helium), while periods 2 and 3 have 8 elements. Periods 4 and 5 have 18 elements. Periods 6 and 7 have 32 elements because the two bottom rows that are separated from the rest of the table belong to those periods.
Hi there!
We can begin by calculating the distance remaining after the reaction time.
Δd = vt
Calculate the distance traveled within this time:
Δd = (16)(.79) = 12.64 m
Subtract from the total distance:
150 - 12.64 = 137.66 m remaining
We can use the following equation to solve for the acceleration necessary:
vf² = vi² + 2ad, where vf = 0 since the train will have slowed down to rest.
Rearrange in terms of "a":
0 = vi² + 2ad
(-vi²) = 2ad
(-vi²)/2d = a
Plug in the given values:
(-(16²))/2(137.66) = a
-256/275.32 = -.9298 m/s²
A)We know the formula of the angular speed is ω = 2π / TWhere T is the time period.When second hand completes one revolution then the time taken is 60s.So T = 60sThen the angular speed of the second hand is ω= 2π / (60s) = 0.1047 rad/sb)When the minute hand completes one revolution the time taken is T = 1 hr = 3600sThen the angular speed of the minute hand is ω =(2π) / (3600s) = 0.001745 rad/sc)When the hour hand completes one revolution then the timeperiod is T = 12hrs = (12)(3600)sThen the angular speed of the hour hand is ω =(2π) / [(12)(3600)s] = 1.45444 x 10^-4 rad/s