3 years ago

Round 24.91 to the nearest tenth. Pls answer fast I need now!! Pls thank you

Mathematics

1 answer:

NISA [10]3 years ago

8 0

Hey there! Let's solve your problem:

The answer to your question is 24.9

This question is asking to round to the nearest tenth.

The number in the tenths place is the number 9.

So, we will remove all the numbers after the 9.

We get the number 24.9

Best of Luck!

You might be interested in

Arrange the steps in the correct order to perform this subtraction problem. 1.1 × 10^3 – 4.9 × 10^2 PUT THESE IN ORDER please A)

Mariana [72]

Answer:

The correct order is,

A, D, C, F, B, G

Step-by-step explanation:

Given subtraction problem,

A) $1.1\times 10^3-4.9\times 10^2$

Make both significant value with the same exponent of 10,

D) $1.1\times 10^3-\frac{10}{10}4.9\times 10^2$

By solving,

C) $1.1\times 10^3-0.49\times 10^3$ $(a^m.a^n=a^{m+n})$

Taking common $10^3$ from both terms,

F) $(1.1-0.49)10^3$

Subtracting,

B) $0.61\times 10^3$

By solving,

G) $6.1\times 10^2$ ( $0.61 = 6.1\times 10^{-1}$ )

5 0

4 years ago

Steve gets paid $50 a week plus $5 for each item he sells. He wants to know how many items he

Charra [1.4K]

<u>Answer:</u>

$50 + 5x > $220

5x> $220 - $50

7 0

3 years ago

Nine less than a number is no more than 8 and is no less than 3

frozen [14]

9 - x < 8 => -x < 8 - 9 => -x < -1 => x > 1

9 - x > 3 => -x > 3 -9 => -x > -6 => x < 6

So the number is between 1 and 6, notation 1 < x < 6

7 0

4 years ago

Add.<br> (-x^3+26x^2-7-13)+(6x^4-x^3+8x+27)<br> express the answer in standard form.

Alex777 [14]

$(-x^3+26x^2-7-13)+(6x^4-x^3+8x+27)\\\\=-x^3+26x^2-7-13+6x^4-x^3+8x+27\\\\=6x^4+(-x^3-x^3)+26x^2+8x+(27-7-13)\\\\=\boxed{6x^4-2x^3+26x^2+8x+7}$

4 0

3 years ago

How do you write 1 hundred 25tens 1one ??

My name is Ann [436]

I think it would be 1251

7 0

3 years ago

Read 2 more answers