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Reika [66]
3 years ago
6

When a distant star explodes, a visible light telescope and s radio telescope located on earth receive signals from the explodin

g star at the same time
which feature of the electromagnetic theory does the evidence support

A. Visible light waves are more energetic than radio waves

B. Radio wavelengths are longer than visible light wavelengths

C. Electromagnetic radiation can have a wide range of frequencies

D. The speed of electromagnetic waves is independent on wavelength
Physics
1 answer:
lorasvet [3.4K]3 years ago
4 0

Answer:

the correct answer is D

Explanation:

When the star explodes the radiation travels through empty space at the speed of light c= 3 10⁸ m/s

This speed has been experimentally proven to be constant, therefore two two instruments arrive at the same time

Therefore the correct answer is D

You might be interested in
what has more momentum, a baseball traveling at 4 m/s or a baseball traveling at 16m/s ? and which has more energy ?
Anna007 [38]
We know the formulas for momentum and energy. But they both involve the mass of
the object, and we don't know the mass of the baseball.  What can we do ?

It's not a catastrophe.  The question only asks which one is bigger.  If we're clever,
we can answer that without ever knowing how much the momentum or the energy
actually is.  We know that both baseballs have the same mass, so let's just call it
' M ' and not worry about what it really is.

<u>Momentum of anything = (mass) x (speed)</u>
Momentum of the first baseball = (M) x (4 m/s) = 4M
Momentum of the second one = (M) x (16 m/s) = 16M
The second baseball has 4 times as much momentum as the first one has.

<u>Kinetic energy of anything = 1/2 (mass) x (speed squared)</u>
KE of the first baseball = 1/2 (M) x (4 squared) = 8M
KE of the second one = 1/2 (M) x (16 squared) = 128M
The second baseball has 16 times as much kinetic energy as the first one has.
3 0
4 years ago
a 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. what is its kinetic energy(KE) when it jumps PLEASE HELP ME
Kay [80]

Answer:

0.91 J

Explanation:

The kinetic energy of an object is given by

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

For the lemming in this problem, when he jumps, we have:

m = 0.0780 kg is the mass

v = 4.84 m/s is the speed

Substituting into the equation, we find:

K=\frac{1}{2}(0.0780)(4.84)^2=0.91 J

8 0
3 years ago
A car's acceleration is 3m/s2. If the car started at rest and it only took 10s for the car to reach this acceleration, what is t
Grace [21]

Answer:

30m/s

Explanation:

From law of motion equation

Vf= Vi + at

Where Vf= final velocity

Vi= initial velocity=0(the car started at rest)

a= acceleration= 3m/s2

t= time= 10s

Then substitute into the equation to get the final velocity.

Vf= 0+(10×3)

Vf= 30m/s

Hence, the car's final velocity is 30m/s

5 0
3 years ago
At which position would a person on Earth be able to view a solar eclipse?<br> A<br> B<br> C<br> D
sweet-ann [11.9K]
The answer would be A, since at that position the Earth is fully/partially being engulfed in a shadow cast by the moon from the sun’s rays.

Hope this helps!
5 0
3 years ago
A body of mass 0.1kg tied by a string is rotating a vertical circle with a speed of 10 m/s of radius a 1 m . what is the tension
allochka39001 [22]

Answer:

The tension experienced in the string at the highest point is approximately 9.019 Newtons

Explanation:

The mass of the body tied to the string, m = 0.1 kg

The path of motion of the mass = Vertical circular motion

The speed of rotation of the stone, v = 10 m/s

The radius of the circular motion path, r = 1 m

The required information = The tension at the highest point, T

At the highest point, the tension, 'T', comprises of the centrifugal force, 'F', acting upwards in the string and the weight, 'W' of the body acting downwards

∴ T = F - W

The \ centrifugal \  force, \ F = \dfrac{m \times v^2}{r}

Weight, W = m × g

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

Therefore;

The centrifugal force, F = 0.1 kg × (10 m/s)²/(1 m) = 10 N

The weight of the mass tied to the string, W ≈ 0.1 kg × 9.81 m/s² = 0.981 N

From which we have;

T = 10 N - 0.981 N = 9.019 N

The tension experienced in the string at the highest point ≈ 9.019 Newtons

8 0
3 years ago
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