Question

A body of mass 0.1kg tied by a string is rotating a vertical circle with a speed of 10 m/s of radius a 1 m . what is the tension experienced by the string at the highest point​

Answer 1

Answer:

The tension experienced in the string at the highest point is approximately 9.019 Newtons

Explanation:

The mass of the body tied to the string, m = 0.1 kg

The path of motion of the mass = Vertical circular motion

The speed of rotation of the stone, v = 10 m/s

The radius of the circular motion path, r = 1 m

The required information = The tension at the highest point, T

At the highest point, the tension, 'T', comprises of the centrifugal force, 'F', acting upwards in the string and the weight, 'W' of the body acting downwards

∴ T = F - W

$The \ centrifugal \ force, \ F = \dfrac{m \times v^2}{r}$

Weight, W = m × g

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

Therefore;

The centrifugal force, F = 0.1 kg × (10 m/s)²/(1 m) = 10 N

The weight of the mass tied to the string, W ≈ 0.1 kg × 9.81 m/s² = 0.981 N

From which we have;

T = 10 N - 0.981 N = 9.019 N

The tension experienced in the string at the highest point ≈ 9.019 Newtons