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GaryK [48]
3 years ago
10

Consider three point charges, q1 = 4.50 C, q2 = 4.50 C, and q3 = 6.30 C, located at the corners of an isosceles triangle. The ch

arges q1 and q2 are 5.00 m apart and form the base. The triangle is 3.50 m high, and q3 is located at the top. Calculate the magnitude and direction of the resultant force on q3.
Physics
1 answer:
Ket [755]3 years ago
6 0

Answer:

See explanation below

Explanation:

In this case, let's draw the triangle so we can see how the resultant force would be.

In the picture below, you have the drawn, and the procedure to solve this.

Hope this helps

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LASIK eye surgery uses pulses of laser light to shave off tissue from the cornea, reshaping it. A typical LASIK laser emits a 1.
QveST [7]

Answer:

a) 6.7 * 10⁴ W  b) 8.5* 10¹⁰ W/m²

Explanation:

a) The power of one laser pulse, by definition of power, is equal to the energy expended during the emission of the pulse, divided by the time during which the energy was present, as follows:

P = ΔE/Δt = 10⁻³ J / 15*10⁻⁹ sec = 6.7* 10⁴ W

b) The intensity, or power density, of the light wave, is just the power that we just calculated in a) divided by the cross-section area traversed by the pulse, which is a circle of 1.0 mm diameter.

So, we can write the following expression:

I = P/A = P / π*(d²/4) = 6.7*10⁴ W /( π*(10⁻³)²/4) m² = 8.5* 10¹⁰ W/m²

3 0
3 years ago
4. A coconut falls from a tree and lands on the ground 2 s later. What
Ulleksa [173]

Answer:

vf=19.6

h=19.6

FROM FIRST EQUATION that is vf=vi+gt

then vf = 0+9.8*2=19.6m/s

FROM SECOND EQUATION that is H=vi*t+1/2gt²

then H=0*2+1/2*9.8*2²=19.6

6 0
3 years ago
Read 2 more answers
Force F = − + ( 8.00 N i 6.00 N j ) ( ) acts on a particle with position vector r = + (3.00 m i 4.00 m j ) ( ) .
jek_recluse [69]

Explanation:

Given that,

Force, F=((-8i)+6j)\ N

Position of the particle, r=(3i+4j)\ m

(a) The toque on a particle about the origin is given by :

\tau=F\times r

\tau=((-8i)+6j) \times (3i+4j)

Taking the cross product of above two vectors, we get the value of torque as :

\tau=(0+0-50k)\ N-m

(b) Let \theta is the angle between r and F. The angle between two vectors is given by :

cos\theta=\dfrac{r.F}{|r|.|F|}

cos\theta=\dfrac{(3i+4j).((-8i)+6j)}{(\sqrt{3^2+4^2} ).(\sqrt{8^2+6^2}) }

cos\theta=\dfrac{0}{50}

\theta=90^{\circ}

6 0
3 years ago
To travel at a constant speed,a car engine provides 24 KW of useful powers. The driving force on the car is 600N.AT what speed d
Whitepunk [10]

Answer: D. 40

Explanation:

Power = Force * Velocity

Force = 600N

Power needs to be converted to Watts:

= 24 * 1,000

= 24,000 W

24,000 = 600 * Velocity

Velocity = 24,000/600

= 40 m/s

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Igoryamba

Answer:

A. 1.

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