All categories

3 years ago

C12H26O + SO3+NaOH ----> C12H25NaSO4+ H2O

Chemistry

1 answer:

Vlad [161]3 years ago

4 0

Answer:

We can solve this by the method of which i solved your one question earlier

so again here molar mass of C12H25NaSO4 is 288.372 and number of moles for 11900 gm of C12H25NaSO4 will be = 11900/288.372

which is almost = 41.26 moles

so to get one mole of C12H25NaSO4 we need one mole of C12H26O

so for 41.26 moles of C12H25NaSO4 it will require 41 26 moles of C12H26O

so the mass of C12H26O = 41.26× its molar mass

C12H26O = 41.26×186.34

= 7688.38 gm!!

so the conclusion is If you need 11900 g of C12H25NaSO4 (Sodium Lauryl Sulfate) you need C12H26O 7688.38 gm !!

Again i d k wether it's right or wrong but i tried my best hope it helped you!!

You might be interested in

The Himalayan mountain range of India was formed at a ____.

Rzqust [24]

Answer:

its answer is b

Explanation:

divergent boundary

7 0

3 years ago

Read 2 more answers

What is the synthetic formula for phenolphthalein?

My name is Ann [436]

Answer:

C20H1404 you have to write it like smaller numbers if you understand

8 0

3 years ago

In this reaction, what roll does the lead (II) nitrate play when 50.0 mL of 0.100M iron (III) chloride are mixed with 50.0 mL of

Aloiza [94]

Answer: The roll of lead (II) nitrate is that it is a limiting reactant of the reaction.

Solution : Given,

Molarity of $FeCl_3$ = 0.1 M

Volume of $FeCl_3$ = 50.0 ml = 0.05 L (1 L = 1000 ml)

Molarity of $Pb(NO_3)_2$ = 0.1 M

Volume of $Pb(NO_3)_2$ = 50.0 ml = 0.05 L

First we have to calculate the moles of $FeCl_3$ and $Pb(NO_3)_2$ .

$\text{ Moles of }FeCl_3=\text{ Molarity}\times \text{ Volume in L}$

$\text{ Moles of }FeCl_3=(0.100M)\times (0.05L)=0.005moles$

$\text{ Moles of }Pb(NO_3)_2=\text{ Molarity}\times \text{ Volume in L}$

$\text{ Moles of }Pb(NO_3)_2=(0.100M)\times (0.05L)=0.005moles$

The balanced chemical reaction is,

$2FeCl_3+3Pb(NO_3)_2\rightarrow 2Fe(NO_3)_3+3PbCl_2$

From the balanced chemical equation, we conclude that

3 moles of lead nitrate react with 2 moles of ferric chloride.

Thus 0.005 moles of lead nitrate react with $=\frac{2}{3}\times 0.005=0.0033$ moles of ferric chloride.

Moles of ferric chloride will be left unreacted = 0.005 - 0.0033 =0.0017 moles

Limiting reagent is the reagent in the reaction which limits the formation of product.

Excess reagent is the reagent in the reaction which is in excess and thus remains unreacted.

Therefore, in the given reaction, lead nitrate is the limiting reagent and ferric chloride is the excess reagent.

7 0

4 years ago

Read 2 more answers

60 POINTS + BRAINLIEST !! PLEASE HELP!!

uranmaximum [27]

To get moles. divide mass by molar mass.Molar mass of
Na is 23
and for Cl is 35.5.
the total molar mass of NaCl is 23+35.5 = 58.5mol/gUse the mass and divide by this number30.22g divide by 58.5mol/g and you will get 0.5166 mole.
Since the molecule has 1 Na to 1 Cl, and that the number of moles for NaCL is 0.5166. All of them would be 0.5166molesNa = 0.5166 x 1 = 0.5166molesCl = 0.5166 x 1 = 0.5166moles
to get number of atoms. Multiply your mole by Avogadro number which is 6.022x10^23Na = 0.5166 x 6.022E23 = 3.111x10^23Cl = 0.5166 x 6.022E23 = 3.111x10^23

5 0

4 years ago

You walk out to your car on a cold January day, and you notice that your tires appear to be flat. You take your car to the shop

Naddik [55]

The answer to this question would be the rate of change

4 0

3 years ago