The two planes are flying in opposite directions.One plane travels at 560miles per hour and the other travels at a speed of 500 miles per hour. As time proceeds, they would travel further from each other and that can be described by the equation that follows:
560(t)+500(t) =2000, since we are given a 2000 distance limit. Then we are to find the time when they are at this distance. Solve for t, which is equal to 0.53 hours or 32 minutes.
Answer:
Option B, Company B
Step-by-step explanation:
<u>Company B since they have a lot more Customer Preference</u>
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Answer: Option B, Company B
Might be 134 because since angle 2 and 8 are lined up like that it is same side exterior angles which means they are supplementary from each other so they will equal 180. So I did 180-46 to get 134, I’m not sure if I’m correct
Answer:
This is poorly written, so i will answer it as it was:
"Let f (x) = |2). Write a function g(x) whose graph is a vertical shrink by a factor of A, followed by a translation 2 units up of the graph of f."
I don't really know what you do mean by I2), so i will answer it in a general way.
First, we do a vertical shrink of factor A.
A must be a number smaller than one and larger than zero., then if g(x) is a vertical shrink of factor A of the graph of f(x), we have that:
g(x) = A*f(x)
As 0 < A < 1
We will have that the graph of g(x) is a vertical compression of the graph of f(x)
Now we do a vertical shift of 2 units up.
A general vertical shift of N units up is written as:
g(x) = f(x) + N
Where N is a positive number.
So in our case, we have:
g(x) = A*f(x) + 2.
Where you will need to replace the values of A and f(x) depending on what the actual question says,
