If a 66.5 g sample of ammonium nitrate (NH4NO3) is dissolved in enough water to make 315 mL of solution, what will be the molari
1 answer:
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The answers are as follows,
1. 4.71 L,
2. 3.29 L,
3. 1634.6 torr
<u>Explanation:</u>
All the above problems can be sorted out using the Boyle's law represents the relationship between the volume and pressure.
It can be expressed as follows,
P1V1 = P2V2
Rearranging the above expression, we get,
1) The first case can be solved as,
2) The second case can be solved as,
3) The third case can be solved as,
Thus the answers for all the three cases are found as,
1. 4.71 L,
2. 3.29 L,
3. 1634.6 torr respectively
Sodium/natrium is a metal from first column group so it should have one 1+ charge. Phosphate ion has 3- charge. That is why there 3 natrium ion for 1 phosphate ion when this molecule is dissolved in water. The ion formula would be:
(Na)
(PO
) ==> 3 Na
+ PO
(Na)
Empirical formula is the simplest ratio of components making up the compound. the molecular formula is the actual ratio of components making up the compound.
the empirical formula is CH₂. We can find the mass of CH₂ one empirical unit and have to then find the number of empirical units in the molecular formula.
Mass of one empirical unit - CH₂ - 12 g/mol x 1 + 1 g/mol x 2 = 12 = 14 g
Molar mass of the compound is - 252 .5 g/mol
number of empirical units = molar mass / mass of empirical unit
=
= 18 units
Therefore molecular formula is - 18 times the empirical formula
molecular formula - CH₂ x 18 = C₁₈H₃₆
molecular formula is C₁₈H₃₆