Answer:
The direction the plane would have to fly to compensate for a wind velocity of 62.0 km/h[N] is 4.5° S of W
Explanation:
The given parameters are;
Velocity of Jet = 792 km/h
Direction of jet velocity = West
Velocity of wind = 62.0 km/h
Direction of wind velocity = North
Therefore, the jet has to have a component of 62.0 km/h South of West to compensate for the wind velocity
The direction of the plane, θ° South of West (S of W) to compensate for the wind is given as follows;
Therefore;
The direction the plane would have to fly to compensate for a wind velocity of 62.0 km/h[N] = 4.5° S of W.
Answer:
c.the spacing between particles increases
To solve this problem we will apply the principles of energy conservation. On the one hand we have that the work done by the non-conservative force is equivalent to -30J while the work done by the conservative force is 50J.
This leads to the direct conclusion that the resulting energy is 20J.
The conservative force is linked to the movement caused by the sum of the two energies, therefore there is an increase in kinetic energy. The decrease in the mechanical energy of the system is directly due to the loss given by the non-conservative force, therefore there is a decrease in mechanical energy.
Therefore the correct answer is A. Kintetic energy increases and mechanical energy decreases.
Because there is no wind, rain, snow, sleet, or people to wear them down,
and no rivers, streams, or floods to cover them over.
Answer:
2795.3 J
Explanation:
distance, d = 28 feet = 8.53 m
Force, F = 80 lb = 356 N
Angle, θ = 23°
Work = F x d x cos θ
W = 356 x 8.53 x cos 23
W = 2795.3 J
Thus, the work done is 2795.3 J.
