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stiks02 [169]
1 year ago
7

PLS HELP What is the mass of hydrogen atoms that is measured at 54 u?

Chemistry
1 answer:
tankabanditka [31]1 year ago
3 0

The mass of hydrogen atoms that is measured at 54 u given the relationship is 89.64×10¯²⁴ g

<h3>Conversion scale </h3>

1 u = 1.66×10¯²⁴ g

<h3>How to determine the mass of hydrogen atoms </h3>
  • Mass of Hydrogen (u) = 54 u
  • Mass of Hydrogen (g) =?

1 u = 1.66×10¯²⁴ g

Therefore

54 u = 54 × 1.66×10¯²⁴ g

54 u = 89.64×10¯²⁴ g

Thus, the mass of the hydrogen atoms measured at 54 u is 89.64×10¯²⁴ g

Learn more about conversion:

brainly.com/question/2139943

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Standard Molar Volume is the volume occupied by one mole of any gas at STP. Remember that "STP" is Standard Temperature and Pressure. Standard temperature is 0 &176:C or 273 K. Standard pressure is 1 atmosphere or 760 mm Hg (also called "torr"). 1 mole of any gas at STP occupies 22.4 liters of volume.

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Bond length is the distance between the centers of two bonded atoms. on the potential energy curve, the bond length is the inter
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Answer:Hence, the bond length in HCl is 125 pm.

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Also given that bond length is the distance between the centers of two bonded atoms. on the potential energy curve, the bond length is the inter-nuclear distance between the two atoms when the potential energy of the system reaches its lowest value. Beyond this if atoms come closer to each other then their will be repulsion between them.

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A piece of unknown metal with mass 30 g is heated to 110.0 °C and dropped into 100.0 g of water at 20.0 °C. The final temperatur
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<u>Answer:</u> The specific heat of metal is 0.821 J/g°C

<u>Explanation:</u>

When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]       ......(1)

where,

q = heat absorbed or released

m_1 = mass of metal = 30 g

m_2 = mass of water = 100 g

T_{final} = final temperature = 25°C

T_1 = initial temperature of metal = 110°C

T_2 = initial temperature of water = 20.0°C

c_1 = specific heat of metal = ?

c_2 = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

30\times c_1\times (25-110)=-[100\times 4.186\times (25-20)]

c_1=0.821J/g^oC

Hence, the specific heat of metal is 0.821 J/g°C

8 0
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Q = 14NA  q =14(6.02×10^23)(10)(1.60×10^−19C) = 1.3×10^7 C.

Mass is the quantity of matter in a physical body. It is also a measure of the body's inertia, the resistance to acceleration when a net force is applied. An object's mass also determines the strength of its gravitational attraction to other bodies.

Learn more about mass here:

brainly.com/question/17067547

#SPJ4

​

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