The dot plots compare the number of raffle tickets sold by boys and girls during a school fund-raiser. Which plot has an outlier
1 answer:
Answer:
Girl's plot
Step-by-step explanation:
The exact question is as follows :
Given - The dot plots compare the number of raffle tickets sold by boys and girls during a school fund-raiser.
To find - Which plot has an outlier?
Proof -
The correct answer is - Girls
Reason -
Girls plot has an outlier because values way outside the majority of the data.
Definition of outlier -
A value that "lies outside" (is much smaller or larger than) most of the other values in a set of data.
Here in the Girl's plot we can see that, all the dots are close but there is one dot that is lies outside
But in Boy's plot all the dots are close to each other , no dot is lies outside to any other dots.
So,
The correct option is -
Girl's plot has an outlier.
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Answer:
Step-by-step explanation:
focus at (-5, -3), and directrix y = -6
Directrix y=-6 so its a vertical parabola
so equation is
(x-h)^2 = 4p(y-k)
(h,k) is the center
P is the distance between focus and vertex
distance between focus and directrix = 2p
distance between -3 and y=-6 is 3
2p = 3
p = 3/2 or p = 1.5
Focus is (h, k+p)
given focus is (-5, -3) so h= -5 and k+p = -3
k+p=-3, plug in 1.5 for p
k + 1.5 = -3
subtract 1.5 on both sides
k = -4.5
(x-h)^2 = 4p(y-k)
divide by 6 on both sides
then subtract 4.5 on both sides
focus at (10, -4), and directrix y = 6.
Directrix y=6 so its a vertical parabola
so equation is
(x-h)^2 = 4p(y-k)
distance between focus and directrix = 2p
distance between -4 and y=6 is -4-6=-10
2p = -10
p = -5
Focus is (h, k+p)
given focus is (10, -4) so h= 10 and k+p = -4
k+p=-4, plug in 5 for p
k - 5 = -4
add 5 on both sides
k = 1
(x-h)^2 = 4p(y-k)
divide by -20 on both sides and add 1 on both sides